In order for us to tell whichever fraction is greater than or lesser than, we need to look for the missing part.
For example, we have 2/3 and 1/3.
2/3 needs to have 1/3 in order to complete the whole.
1/3 needs to have 2/3 in order to complete the whole.
1/3 < 2/3
<span>So 2/3 is bigger than 1//3</span>
Answer:
C
Step-by-step explanation:
Ferdinand's equipment is higher than Rachel's equipment.
The present age of father is 86 years old and present age of son is 48 years old
<em><u>Solution:</u></em>
Given that, a father is now 38 years older than his son
Ten years ago he was twice as old as his son
Let "x" be the age of son now
Therefore, from given,
Father age now = 38 + age of son now
Father age now = 38 + x
<em><u>Ten years ago he was twice as old as his son</u></em>
Age of son ten years ago = age of son now - 10
Age of son ten years ago = x - 10
Age of father ten years ago = 38 + x - 10
Then we get,
Age of father ten years ago = twice the age of son ten years ago
38 + x - 10 = 2(x - 10)
28 + x = 2x - 20
2x - x = 28 + 20
x = 48
Thus son age now is 48 years old
Father age now = x + 38 = 48 + 38 = 86
Thus present age of father is 86 years old and present age of son is 48 years old
<u>Question 1 solution:</u>
You have two unknowns here:
Let the Water current speed = W
Let Rita's average speed = R
We are given <em>two </em>situations, where we can form <em>two equations</em>, and therefore solve for the <em>two unknowns, W, R</em>:
Part 1) W→ , R←(against current, upstream)
If Rita is paddling at 2mi/hr against the current, this means that the current is trying to slow her down. If you look at the direction of the water, it is "opposing" Rita, it is "opposite", therefore, our equation must have a negative sign for water<span>:
</span>R–W=2 - equation 1
Part 2) W→ , R<span>→</span>(with current)
Therefore, R+W=3 - equation 2
From equation 1, W=R-2,
Substitute into equation 2.
R+(R–2)=3
2R=5
R=5/2mi/hr
So when W=0 (still), R=5/2mi/hr
Finding the water speed using the same rearranging and substituting process:
1... R=2+W
2... (2+W)+W=3
2W=1
W=1/2mi/hr
Answer:
50 pounds
Step-by-step explanation:
Dan and june mix two kind of feed for pedigreed dogs
Feed A worth is $0.26 per pound
Feed B worth is $0.40 per pound
Let x represent the cheaper amount of feed and y the costlier type of feed
x+y= 70..........equation 1
0.26x + 0.40y= 0.30×70
0.26x + 0.40y= 21.........equation 2
From equation 1
x + y= 70
x= 70-y
Substitutes 70-y for x in equation 2
0.26(70-y) + 0.40y= 21
18.2-0.26y+0.40y= 21
18.2+0.14y= 21
0.14y= 21-18.2
0.14y= 2.8
Divide both sides by the coefficient of y which is 0.14
0.14y/0.14= 2.8/0.14
y= 20
Substitute 20 for y in equation 1
x + y= 70
x + 20= 70
x= 70-20
x = 50
Hence Dan and june should use 50 pounds of the cheaper kind in the mix
