You can try finding the roots of the given quadratic equation to get to the solution of the equation.
There are two solutions to the given quadratic equation
<h3>How to find the roots of a quadratic equation?</h3>
Suppose that the given quadratic equation is 
Then its roots are given as:
<h3>How to find the solution to the given equation?</h3>
First we will convert it in the aforesaid standard form.
Thus, we have
a = 1. b = -114, c = 23
Using the formula for getting the roots of a quadratic equation,
Thus, there are two solutions to the given quadratic equation
Learn more here about quadratic equations here:
brainly.com/question/3358603
Answer: (i) A = 2500 (
(ii) A =$ 4,974.47
Step-by-step explanation:'
The exponential function is given as :
A = P
Where :
A = amount
P = principal
r = rate %
n = number of years
substituting , the exponential function to model the situation becomes
A = 2500 (
(ii) when n = 20 , the Amount becomes
A = 2500(
A =$ 4,974.47
Answer:
$0.58
Step-by-step explanation:
There are 8 pencils per package. To find the value of each pencil, divide the cost by 8
4.64/8 = $0.58
According to Vieta's Formulas, if
are solutions of a given quadratic equation:
Then:
is the completely factored form of
.
If choose
, then:
So, according to Vieta's formula, we can get:
But
:
![d^4-8d^2+16=(d^2-4)^2=[(d+2)(d-2)]^2=(d+2)^2(d-2)^2](https://tex.z-dn.net/?f=d%5E4-8d%5E2%2B16%3D%28d%5E2-4%29%5E2%3D%5B%28d%2B2%29%28d-2%29%5D%5E2%3D%28d%2B2%29%5E2%28d-2%29%5E2)
Answer:
The center/ mean will almost be equal, and the variability of simulation B will be higher than the variability of simulation A.
Step-by-step explanation:
Solution
Normally, a distribution sample is mostly affected by sample size.
As a rule, sampling error decreases by half by increasing the sample size four times.
In this case, B sample is 2 times higher the A sample size.
Now, the Mean sampling error is affected and is not higher for A.
But it's sample is huge for this, Thus, they are almost equal
Variability of simulation decreases with increase in number of trials. A has less variability.
With increase number of trials, variability of simulation decreases, so A has less variability.
