Question

Write a cosine function that has an amplitude of 3, a midline of 2 and a period

Answer 1

Answer:

f(x) = 3 cos  (2Pi / period value ; x  )+ 2

or see answer using 2 as the period see answer in bold below.

Step-by-step explanation:

cosine function amplitude of 3 is  A = 3

The period is used to find B

You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle

C is the adding value.

Acos (Bx) + C

A = 3

Bx =  2 pi / period

C = + 2

However f 2 is also the period found

then we just plug in 2 to above formula

f(x) = 3 cos  (2Pi / 2 ; x  )+ 2

f(x) = 3cos (x pi) + 2