Write a cosine function that has an amplitude of 3, a midline of 2 and a period
1 answer:
Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
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Answer:
35.34 atoms will be present after 14,325 years.
Step-by-step explanation:
Given : Carbon-14 has a half-life of approximately 5,730 years. This exponential decay can be modeled with the function N(t) = N0. If an organism had 200 atoms of carbon-14 at death.
To find : How many atoms will be present after 14,325 years?
Solution :
The half-life exponential function modeled is
Where, is the initial atoms
N is the total number of atoms.
t=14,325 years is the time
h=5,730 years is the half-life time
Substitute the value in the formula,
Therefore, 35.34 atoms will be present after 14,325 years.