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-Dominant- [34]
3 years ago
6

Write a cosine function that has an amplitude of 3, a midline of 2 and a period

Mathematics
1 answer:
marissa [1.9K]3 years ago
6 0

Answer:

f(x) = 3 cos  (2Pi / period value ; x  )+ 2

or see answer using 2 as the period see answer in bold below.

Step-by-step explanation:

cosine function amplitude of 3 is  A = 3

The period is used to find B

You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle

C is the adding value.

Acos (Bx) + C

A = 3

Bx =  2 pi / period

C = + 2

However f 2 is also the period found

then we just plug in 2 to above formula

f(x) = 3 cos  (2Pi / 2 ; x  )+ 2

f(x) = 3cos (x pi) + 2

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3 years ago
If f(x)=sinx−1/cos2x, then limx→π2f(x) is equivalent to which of the following?
Harrizon [31]

Answer:

2

Step-by-step explanation:

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tangare [24]

Answer:

Step-by-step explanation:

15s-100=350

the last one

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8 0
2 years ago
Read 2 more answers
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Naddik [55]
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Without graphing is the system independent, dependent, or inconsistent?
rewona [7]
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3 years ago
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