Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
The coordinates for the pre-image are P(1,3), Q(4,4), R(4,1), and S(1, -1).
The transformation is 4 units left, and 4 units down.
That means we must subtract 4 units to x-coordinates, and subtract 4 units from y-coordinates. So, the image has coordinates P'(-3,-1), Q'(0,0), R'(0, -3), and S'(-3, -5).
The image below shows the image and pre-image.
