Answer:
The length of the pool is 28 meters and the width of the pool is 10.5 meters.
Step-by-step explanation:
In the scale drawing of Joe, the community pool has (length : width) = 8 : 3
Let the actual length of the pool is 8x meters and the actual width is 3x meters.
Now, given that the actual pool has a perimeter of 77 meters.
So, 2(8x + 3x) = 77
⇒ 22x = 77
⇒ x = 3.5
So, the length of the pool is 8x = 8(3.5) = 28 meters and the width of the pool is 3x = 3(3.5) = 10.5 meters. (Answer)
Answer:
<h3> in square feet</h3>
Step-by-step explanation:
Area of anything is<u> allways </u>reported <u>in square units</u>. Usually that is square of given unit because it's the simplest way:
R = 50 ft
A = πR² = π•(50 ft)² = π • 50 ft • 50 ft = 2500π ft² ≈ 7854 ft²
{Of course you can re-calculate the units, ex.:
3 feet = 1 yard so 50 ft = 50/3 yd then
A = πR² = π•(50/3 yd)² = π • 50/3 yd • 50/3 yd = 2500/9 π yd² ≈ 872.7 yd² }
Answer:
false buddy that is the answer