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2 years ago

6+8x-9=11x+14-3x, can this equation be always, sometimes, or never true.

1 answer:

4 0

<span>6 + 8x - 9 = 11x + 14 - 3x

8x + 3x - 11x = 14 + 9 -6

11x - 11x = 17

0 =17 This is not true.

When we have this kind of format, we know it is Never true.
</span>

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Approximately how many times greater is 6 x 10^-5 than 5 x 10^-9

8_murik_8 [283]

Answer: $6 \times 10^{-5}$ is $1.2 \times 10^4.$ times greater than $5 \times 10^{-9}$ .

Step-by-step explanation:

We are given two numbers.

First number : $6 \times 10^{-5}$ .

Second number : $5 \times 10^{-9}$ .

In order to find how many times $6 \times 10^{-5}$ is greater than $5 \times 10^{-9}$ , we need to divide first number by second number.

Therefore,

$6 \times 10^{-5}$ ÷ $5 \times 10^{-9}$

or $\frac{6 \times 10^{-5}}{5 \times 10^{-9}}$

First we would divide 6 by 5.

On dividing 6 by 5, we get 1.2.

Now, we would divide 10^-5 by 10^-9.

In order to divide them, we can apply quotient rule of exponents $\frac{a^m}{a^n} =a^{m-n}$ .

We get

$\frac{10^{-5}}{10^{-9}} = 10^{-5-(-9)} = 10^{-5+9} = 10^4$ .

Therefore,

$\frac{6 \times 10^{-5}}{5 \times 10^{-9}}$ = $1.2 \times 10^4.$

So, we could say finally $6 \times 10^{-5}$ is $1.2 \times 10^4.$ times greater than $5 \times 10^{-9}$ .

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