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telo118 [61]
3 years ago
12

6+8x-9=11x+14-3x, can this equation be always, sometimes, or never true.

Mathematics
1 answer:
loris [4]3 years ago
4 0
<span>6 + 8x - 9 = 11x + 14 - 3x

8x + 3x - 11x =  14 + 9 -6

11x - 11x =  17

0 =17    This is not true.

When we have this kind of format, we know it is Never true.
</span>
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Step-by-step explanation:

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3 years ago
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The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers and together form a pyt
Leni [432]
If all three side lengths are INTEGERS and form PYTHAGOREAN TRIPLE then we know decimals are not allowed

if 24 and 51 are both legs then
24^{2} +  51^{2} =  x^{2}
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and squre root of that gives us 56.364.... NOT an integer

So that means one of them is not a leg and since hypotenuse is longer than both legs, 51 must be the hypotenuse so to get the third side

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7 0
3 years ago
Please hurry! If you don't know it, that's okay.
makvit [3.9K]

Answer:

The answer is (x,y)=(-10,-7)

Step-by-step explanation:

  • The solution comes from replace x= -10 into the equation of y=2/5 x -3.
  • Replacement of x= -10 into y = 2/5 x -3 results: y=\frac{2}{5}\times{(-10)}-3=2\times{(-2)} -3=-4-3=-7.
7 0
3 years ago
Need help quickly! Thanks
Rzqust [24]

Answer:

y = -2^x

Step-by-step explanation:

If the equation of a function is in the form of y = h(x)

When the graph of this function is reflected across x-axis,

Transformed function will be,

y = -h(x)

Further reflected across y-axis, then the transformed function will be,

y = -h(-x)

By this rule,

Given equation when reflected across x-axis,

y = -(\frac{1}{2})^{x}

Further reflected across y-axis,

y = -(\frac{1}{2})^{-x}

y = -(2^{-1})^x

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5 0
3 years ago
Solve using elimination. -7x – 5y = -4 7x + 9y = -4
Brut [27]
-7x-5y=-47x+9y=-4

combine like terms to cross out the 7x
solve for y, to get -2
plug it back in to one of the equations and x is 2

y=-2
x=2
5 0
3 years ago
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