6+8x-9=11x+14-3x, can this equation be always, sometimes, or never true.
1 answer:
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Answer:
Step-by-step explanation:
i) z = -32
ii)
Answer:
11). m∠W = 70°
12). m∠M = 95°
13). m∠Q = 135°
14). m∠Q = 55°
15). m∠X = 110°
Step-by-step explanation:
11). m∠W + m∠X = 180° [Consecutive interior angles]
(24x - 2) + (36x + 2) = 180°
60x = 180°
x =
x = 3
Therefore, m∠W = (24x - 2)°
m∠W = (24×3 - 2)
= 72 - 2
= 70°
Since opposite angles of a parallelogram are equal in measure.
m∠Y = m∠W = 70°
12). m∠J + m∠K = 180° [Consecutive interior angles]
(6x + 19) + (8x + 7) = 180°
14x + 26 = 180
14x = 180 - 26
14x = 154
x =
x = 11
m∠K = (8x + 7)
m∠K = 8×11 + 7
m∠K = 95°
Since m∠M = m∠K
Therefore, m∠M = 95°
13). m∠Q = m∠S [Opposite angles of a parallelogram]
x + 135 = 2x + 135
2x - x = 0
x = 0
Therefore, m∠Q = 135°
14). m∠Q = m∠S [Opposite angles of a parallelogram]
14x - 1 = 13x + 3
14x - 13x = 3 + 1
x = 4
m∠Q = (13x + 3)
= 13×4 + 3
= 52 + 3
m∠Q = 55°
15). m∠Z = m∠X
(19x - 4) = (17x + 8)
19x - 17x = 12
2x = 12
x = 6
m∠X = (17x + 8)°
m∠X = 17×6 + 8
m∠X = 110°