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3 years ago

Evaluate the expression (2x + y) +5 when x = 4, y = 10.

Mathematics

2 answers:

stiv31 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

The question is a under substitution, that's a given number will be used to replace a letter

So back to the question

(2x+y)+5

And x is said to be 4 and y is 10

Let's start solving

(2(4)+10)+5

Hope you understand it to this extent,any where you see x you will have to put the given value for x same goes for y

(8+10)+5

18+5

Therefore the evaluation is 23

Maru [420]3 years ago

7 0

Answer:

The answer is 23.

Step-by-step explanation:

Our equation here is (2x + y) + 5.

If x=4, and y=10, let's plug that in into our variables, and simplify!

[2(4) + (10)] + 5

= [8+10] + 5

=[18] +5

=23

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On Monday Jordan biked 2 3/4 miles on Wednesday he biked twice as many miles then he did on Monday on Friday Jordan biked 8 1/4

zimovet [89]

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4 years ago

Simplify: 12x3 - 3(2x3 + 4x -1) - 5x + 7

BlackZzzverrR [31]

Answer:

6x^3 − 17x + 10

Step-by-step explanation:

12x3 - 3(2x3 + 4x -1) - 5x + 7 Simplifed is 6x^3 − 17x + 10

7 0

3 years ago

Read 2 more answers

Use the Trapezoidal Rule, the Midpoint Rule, and Simpson's Rule to approximate the given integral with the specified value of n.

Otrada [13]

I guess the "5" is supposed to represent the integral sign?

$I=\displaystyle\int_1^4\ln t\,\mathrm dt$

With $n=10$ subintervals, we split up the domain of integration as

[1, 13/10], [13/10, 8/5], [8/5, 19/10], ... , [37/10, 4]

For each rule, it will help to have a sequence that determines the end points of each subinterval. This is easily, since they form arithmetic sequences. Left endpoints are generated according to

$\ell_i=1+\dfrac{3(i-1)}{10}$

and right endpoints are given by

$r_i=1+\dfrac{3i}{10}$

where $1\le i\le10$ .

a. For the trapezoidal rule, we approximate the area under the curve over each subinterval with the area of a trapezoid with "height" equal to the length of each subinterval, $\dfrac{4-1}{10}=\dfrac3{10}$ , and "bases" equal to the values of $\ln t$ at both endpoints of each subinterval. The area of the trapezoid over the $i$ -th subinterval is

$\dfrac{\ln\ell_i+\ln r_i}2\dfrac3{10}=\dfrac3{20}\ln(ell_ir_i)$

Then the integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac3{20}\ln(\ell_ir_i)\approx\boxed{2.540}$

b. For the midpoint rule, we take the rectangle over each subinterval with base length equal to the length of each subinterval and height equal to the value of $\ln t$ at the average of the subinterval's endpoints, $\dfrac{\ell_i+r_i}2$ . The area of the rectangle over the $i$ -th subinterval is then

$\ln\left(\dfrac{\ell_i+r_i}2\right)\dfrac3{10}$

so the integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac3{10}\ln\left(\dfrac{\ell_i+r_i}2\right)\approx\boxed{2.548}$

c. For Simpson's rule, we find a quadratic interpolation of $\ln t$ over each subinterval given by

$P(t_i)=\ln\ell_i\dfrac{(t-m_i)(t-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+\ln m_i\dfrac{(t-\ell_i)(t-r_i)}{(m_i-\ell_i)(m_i-r_i)}+\ln r_i\dfrac{(t-\ell_i)(t-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

where $m_i$ is the midpoint of the $i$ -th subinterval,

$m_i=\dfrac{\ell_i+r_i}2$

Then the integral $I$ is equal to the sum of the integrals of each interpolation over the corresponding $i$ -th subinterval.

$I\approx\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}P(t_i)\,\mathrm dt$

It's easy to show that

$\displaystyle\int_{\ell_i}^{r_i}P(t_i)\,\mathrm dt=\frac{r_i-\ell_i}6(\ln\ell_i+4\ln m_i+\ln r_i)$

so that the value of the overall integral is approximately

$I\approx\displaystyle\sum_{i=1}^{10}\frac{r_i-\ell_i}6(\ln\ell_i+4\ln m_i+\ln r_i)\approx\boxed{2.545}$

4 0

4 years ago

Which is greater<br> 15) 2/5 or 3/10 <br>16) 1/5 or 1/4 <br>17) 3/4 or 18/24

katen-ka-za [31]

2/5 because it’s the same as 4/10
1/4 because it’s 5/20 and 1/5 is 4/20
they are both the same because 3/4 is the same as 18/24
hope that helps!

8 0

3 years ago

Read 2 more answers

Triangle ABC was translated 2 units to the right and 3 units down. Which rule describes the translation that was applied to tria

VashaNatasha [74]

Answer:

The answer is B. When something is being translated right, it will be represented with an addition sign, while if it's being translated left, it will be represented with an subtraction sign. The same thing applies when it is translated up and down. Up is represented with an addition sign, while down is represented with a subtraction sign.

Step-by-step explanation:

An example of this can be a point being translated 3 units to the left and 3 units upwards. The translation would look like this:

(x-3, y-3) :)

7 0

3 years ago