Answer:
8 because it is composite.
Step-by-step explanation:
Answer:
A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
The margin of error of the interval is given by:

In this problem, we have that:

99.5% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?
This is n when M = 0.07. So







A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07
(3-6)/(8-2)+(7/2)
Do what is in the parenthesis first.
-3/6+3.5
-0.5+3.5=3
Therefore, your answer is 3
Hope this Helps!
Y - 6= 5(x - 2)
y - 6 = 5x - 10
y= 5x - 4
10%= .10
.10(11,800)= 1,180
1,180(8)= 9,440
11,800- 9,440= 2,360
= $2,360
I hope this helped.