Answer:
There are 8 tens and 2 ones
Step-by-step explanation:
Hope this helps
It will be 14.
i’ll attach an image to show work
Answer:
y= 13/2x +12
Step-by-step explanation:
so first move expression to right hand side
13x-2y+24=0
2y= 13x+24
then divide every term by 2 to cancel out 2
2y/2 = 13x/2 + 24/2
and then you get your final answer
Answer:
Because each term of the sequence generates numbers with more than 1 and itself as dividers
Step-by-step explanation:
Just for the sake of correction.
1) Let's consider that
n! =n(n-1)(n-2)(n-3)...
2)And examine some numbers of that sequence above:
Every Natural number plugged in n, and added by two will a be an even number not only divisible by two, but in some cases by other numbers for example,n=4, then 4!+2=26 which has four dividers.
3) Similarly, the same happens to
and 
Where we can find many dividers.
There's an example of a sequence, let's start with a prime number greater than 1
Let n=11
That's a long sequence of consecutive composite numbers, n=11.
First, define the area of a triangle: A = 1/2bh. Let A = 16, and since it’s a right triangle, the base and the height can easily be translated to its two legs. Let one leg = x, and the other = x + 4. So this would give you the equation: 16 = .5(x)(x+4). Distribute so 16 = .5x^2 + 2x. You might want to get rid of the decimal/fraction, so multiply everything by 2 and this would give you 32 = x^2 + 4x. Recognizing that this will be a quadratic equation let x = 0 and bring everything unto one side, so 0 = x^2 + 4x - 32. Factor. 0 = (x+8)(x-4). Since a leg cannot be negative, x can only equal 4. This means that one leg is 4 and the other is 8.
