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serious [3.7K]
3 years ago
9

Find the 32nd term of this sequence: 9,4,-1,-6,-11,....

Mathematics
2 answers:
crimeas [40]3 years ago
3 0

Answer:

-146, but I could be wrong, so wait till someone else answers

Step-by-step explanation:

frez [133]3 years ago
3 0

t=a+(n-1)d

t=9+(32-1)(-5)

t=-146

Note you can use this equation.

Where n is the term

t is your value

d is your common difference or rate

Where a is your starting value

The -1 is there because your first term counts as a term and 9 is your first terms.

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If a triangle has a height of 12 in and a base of 5 inbwhats the area
Yuliya22 [10]
Area of a triangle
A=h x b/2=12 x 5/2=30
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7 0
3 years ago
What do you notice about these numbers? VeryEASY 4 YOU just EXPLANATION
BabaBlast [244]

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8 0
3 years ago
Michelle is buying carpet for a room with the dimensions shown. Michelle calculates that the area she will cover with carpet is
butalik [34]

The area of the room is 147\frac{1}{2} square feet so Michelle's reasoning was incorrect.

Step-by-step explanation:

Step 1:

To calculate the area of the given room, we divide the unknown shape into known shapes.

The room's shape is made of 2 rectangles.

The area of a rectangle is the product of its length and its width.

One rectangle has a length of 10 feet and a width of 12\frac{1}{2} feet.

The other rectangle has a length of 15-10=5 feet and a width of 4\frac{1}{2} feet.

Step 2:

The area of the first rectangle = (10)(12\frac{1}{2} )= (10)(12.5)= 125 square feet.

The area of the second rectangle = (10)(4\frac{1}{2} )= (5)(4.5)= 22.5 square feet.

The total area of the room = 125+22.5 = 147.5 = 147 \frac{1}{2} square feet.

The area of the room is 147\frac{1}{2} square feet so Michelle's reasoning was incorrect.

7 0
3 years ago
A friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work
lubasha [3.4K]

Answer:

The probability that he drove the small car is 0.318.

Step-by-step explanation:

We are given that a friend who works in a big city owns two cars, one small and one large. One-quarter of the time he drives the small car to work, and three-quarters of the time he takes the large car.

If he takes the small car, he usually has little trouble parking and so is at work on time with probability 0.7. If he takes the large car, he is on time to work with probability 0.5.

Let the Probability that he drives the small car = P(S) = \frac{1}{4} = 0.25

Probability that he drives the large car = P(L) = \frac{3}{4} = 0.75

Also, let WT = event that he is at work on time

So, Probability that he is at work on time given that he takes the small car = P(WT / S) = 0.7

Probability that he is at work on time given that he takes the large car = P(WT / L) = 0.5

Now, given that he was at work on time on a particular morning, the probability that he drove the small car is given by = P(S / WT)

We will use the concept of Bayes' Theorem for calculating above probability;

So,    P(S / WT)  =  \frac{P(S) \times P(WT/S)}{P(S) \times P(WT/S)+P(L) \times P(WT/L)}

                          =  \frac{0.25 \times 0.7}{0.25 \times 0.7+0.75 \times 0.5}

                          =  \frac{0.175}{0.55}

                          =  <u>0.318</u>

Hence, the required probability is 0.318.

8 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Snowcat [4.5K]

Answer:

An=A(n-1)-4 where A=7

Step-by-step explanation:

3 0
3 years ago
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