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Temka [501]
3 years ago
11

Which graph shows the solution to the inequality −2(2x+3)≤26?

Mathematics
1 answer:
krok68 [10]3 years ago
5 0

Answer:

x≥−8

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−4x−6≤26

Step 2: Add 6 to both sides.

−4x−6+6≤26+6

−4x≤32

Step 3: Divide both sides by -4.

−4x/−4 ≤ 32/−4

x≥−8

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x=2 and y=1

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Bo, Ryan and Zach walked 1/4 miles from school to Bo’s house. They walked 4/6 miles from Bo's House to the park what is the tota
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Describe how to find the domain of a square root function just by looking at the function.
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3 years ago
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
4 years ago
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