When dividing 0.006 divided by 0.024 it becomes 0.025, i did it by calculator so dont give me credit for this lol
We have been given that the quadratic equation models the path of a heavy ball through the air, where y represents the height in feet and x represents time in seconds. We are asked to find the time when ball will hit the ground.
The ball will hit the ground, when height of ball above ground will be 0. So we will equate our given quadratic equation with 0 and solve for x.
We will use quadratic formula to solve our given problem.
, where
b = Coefficient of x term,
a = Coefficient of term,
c = Constant.
Since time cannot be negative, therefore, the ball will hit the ground after 10 seconds.
Plot the points on a graph and join them to form a closed figure. two sides that are parallel shows it is a trapezoid
Answer:
X= Y=
Step-by-step explanation:
The first one is 45-45-90 right angled isosceles triangle.
The length of the hypotenuse ie.X can be found with the help of Pythagoras Theorem.
where a and b are the remaining sides of the triangle,
X=
In the second triangle we have to apply trigonometry,
cos θ=
cos 30°=
=
Thus, Y= inches
To answer by systems of elimination, you add equations together to eliminate variables if they have the same amount of negative variables in one as the positive variables in another.
For example, in number one.
x - y = 11
2x + y = 19
Both equations contain a variable expressed in the same numbers of negative and positive in each of them, one positive y and negative y. This lets us add the equations together.
x + 2x = 3x
11 + 19 = 30
3x = 30
x = 10
Now that we know that x = 10, we can plug it into the first equation, x - y = 11 to find y.
x - y = 11
10 - y = 11
y = -1
For the second one,
4x + 8y = 20
-4x + 2y = 30
Negate the x's since there is the same and opposite amount, while adding the rest of the equations together.
8y + 2y = 10y
20 + 30 = 50
10y = 50
y = 5
Plug it into the initial equation to find x
4x + 8(5) = 20
4x + 40 = 20
Subtract 40 from both sides
4x = -20
x = -5
For the third equation,
-6x + 5y = 1
6x +4y = -10
Negate the x's, add the rest together
5y + 4y = 9y
1 - 10 = -9
9y = -9
y = -1
Plug it into the first equation to find x
-6x + 5y = 1
-6x + 5(-1) = 1
-6x - 5 = 1
Add five to both sides
-6x = 6
Divide both sides by negative 6
x = -1
When the problems do not have the same value of opposite versions of current numbers, for example:
3x + 4y = 6
-6x +g = 6
You can multiply an entire equation to get similar numbers of a variable.
For example, you can multiply the first equation entirely by 2 to get the same number of positive x's to the negative x's in the second one, changing it to 6x x 8y = 12.
Hope I helped.