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3 years ago

100 POINTS IF YOU GUESS RIGHT PLEASE HELP

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

6 0

Answer:

5 and 3

Step-by-step explanation:

Let the numbers be x and y.

We have:

x + y = 8
x - y = 2

Sum the two and find x:

2x = 10
x = 5

Find y:

y = 5 - 2
y = 3

You might be interested in

If the subspace of all solutions of Ax 0 has a basis consisting of vectors and if A is a matrix, what is the rank of A

Nuetrik [128]

Question: If the subspace of all solutions of

Ax = 0

has a basis consisting of vectors and if A is a matrix, what is the rank of A.

Note: The rank of A can only be determined if the dimension of the matrix A is given, and the number of vectors is known. Here in this question, neither the dimension, nor the number of vectors is given.

Assume: The number of vectors is 3, and the dimension is 5 × 8.

Answer:

The rank of the matrix A is 5.

Step-by-step explanation:

In the standard basis of the linear transformation:

f : R^8 → R^5, x↦Ax

the matrix A is a representation.

and the dimension of kernel of A, written as dim(kerA) is 3.

By the rank-nullity theorem, rank of matrix A is equal to the subtraction of the dimension of the kernel of A from the dimension of R^8.

That is:

rank(A) = dim(R^8) - dim(kerA)

= 8 - 3

= 5

4 0

3 years ago

HELP PLEASE! FINALSSS!

fenix001 [56]

Answer:

A:28/500

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

NEED ASAP plz. I will also mark brainiest! Don't just take points, I will report you.

PilotLPTM [1.2K]

Part A:

You may choose the two lines connecting the origin and points A and B, and choose the portion of the space between them.

The line between the origin and A is

$y = 3x$

We want everything below this line (line included), so the first inequality is

$y \leq 3x$

The line between the origin and B is

$y = \dfrac{1}{3}x$

We want everything above this line (line included), so the second inequality is

$y \geq \dfrac{1}{3}x$

Create a system with these two inequalities and you'll have an area including only points A and B

Part B:

To verify the solutions, we can plug the coordinates of A and B in this system and check that we get something true: the coordinates of point A are (1,3), while the coordinates of point B are (3,1). The system becomes:

$A:\begin{cases}3 \leq 3\cdot 1\\3 \geq \frac{1}{3}\cdot 1\end{cases},\quad B:\begin{cases}1 \leq 3\cdot 3\\1 \geq \frac{1}{3}\cdot 3\end{cases}$

Which means

$A:\begin{cases}3 \leq 3\\3 \geq \frac{1}{3}\end{cases},\quad B:\begin{cases}1 \leq 9\\1 \geq 1\end{cases}$

And these are all true. So, the system is satisfied, which means that the points belong to the shaded area.

Part C

If you draw the line, you'll see that the only points that lay below the line are B and C. In fact, if we plug the coordinates we have

$B:\ 1$

And this are both true. You can check the coordinates of all other points, and see that they won't satisfy the inequality y<3x-6

3 0

3 years ago

26.4 into fraction what is - 6.4 into a fraction

denis23 [38]

26.4 into fraction
26.4/1 * 100/100

2640/100

slash the zeros

264/10

simplify

132/5

turn it into a mixed fraction and you get

26 2/5

3 0

3 years ago

PLZ HELP I WILL MARK AS BRAINLIEST

-Dominant- [34]

Answer:

7 square units

Step-by-step explanation:

As with many geometry problems, there are several ways you can work this.

Label the lower left and lower right vertices of the rectangle points W and E, respectively. You can subtract the areas of triangles WSR and EQR from the area of trapezoid WSQE to find the area of triangle QRS.

The applicable formulas are ...

area of a trapezoid: A = (1/2)(b1 +b2)h

area of a triangle: A = (1/2)bh

So, our areas are ...

AQRS = AWSQE - AWSR - AEQR

= (1/2)(WS +EQ)WE -(1/2)(WS)(WR) -(1/2)(EQ)(ER)

Factoring out 1/2, we have ...

= (1/2)((2+5)·4 -2·2 -5·2)

= (1/2)(28 -4 -10) = 7 . . . . square units

4 0

3 years ago