Ask question

Ask question

All categories

2 years ago

8

An arc subtends an angle of 72 degree at the circumference of a circle of radius 5 cm. calculate the length of the arc in terms

of pie

1 answer:

Irina-Kira [14]2 years ago

4 0

Hope you understand the solution. Call my attention if you need any help

You might be interested in

Find the volume of the cone. Round your answer to the nearest tenth if necessary. Use 3.14 for it.

Korolek [52]

Answer:

452.448cm^3

Step-by-step explanation:

Given data

Height= 25cm

Diamter= 12cm

Radius= 6cm

The expression for the volume of a cone is given as

V= 1/3*πr^2h

Substitute

V= 1/3*3.142*6^2*25

V= 1/3*3.142*36*12

V= 1/3*1357.344

V=452.448cm^3

Hence the volume is 452.448cm^3

8 0

2 years ago

The messure of < bls is 90 degrees . Explain why < lsb and < lbs must be complementary

Kaylis [27]

Because they are the same angle and both equal 90 degrees.

6 0

3 years ago

Four different sets of objects contain 2,5,6, and 7 objects, respectively. How many unique combinations can be formed by picking

Ilia_Sergeevich [38]

There are 2 choices for the first set, and 5 choices for the second set. Each of the 2 choices from the first set can be combined with each of the 5 choices from the second set. Therefore there are 2 times 5 combinations from the first and second sets. Continuing this reasoning, the total number of unique combinations of one object from each set is:
$2\times5\times\times6\times7=420\ combinations$

8 0

3 years ago

Ace or expert pls help

jolli1 [7]

Answer:

Step-by-step explanation:

-0.25

-1/3

1/4

0.3

3 0

2 years ago

Read 2 more answers

The class sizes of elementary school classes in a public school district are normally distributed with an unknown population mea

weqwewe [10]

Answer: $(17.14,\ 22.86)$

Step-by-step explanation:

The confidence interval estimate for the population mean is given by :-

$\overline{x}\pm ME$ , where $\overline{x}$ is the sample mean and ME is the margin of error.

Given : Sample mean: $\overline{x}=20$

The margin of error for a 98% confidence interval estimate for the population mean using the Student's t-distribution : $ME=2.86$

Now, the confidence interval estimate for the population mean will be :-

$20\pm2.86=(20-2.86,\ 20+2.86)=(17.14,\ 22.86)$

Hence, the 98% confidence interval estimate for the population mean using the Student's t-distribution = $(17.14,\ 22.86)$

8 0

3 years ago