<h3>
Answer: 2p + 3q</h3>
Work Shown:
log(200) = log(2^3*5^2)
log(200) = log(2^3) + log(5^2)
log(200) = 3*log(2) + 2*log(5)
log(200) = 3*q + 2*p
log(200) = 2p + 3q
The log rules I used were
log(A*B) = log(A)+log(B)
log(A^B) = B*log(A)
The equation for interest is
'Initial amount (interest rate in decimal form) ^ times compounded EX: years'
your equation would be
400(1.04)^10
which equals 592.097713 (not rounded)
M=72 that’s the best I can give you lol not sure if that helps any