Answer:
0.6210
Step-by-step explanation:
Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries
Sample size n =87
Sample proportion will follow a normal distribution with p =0.39
and standard error = 
the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
=
There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
Answer:
It equals 3, but if you add two negatives inside of the parenthesis, then it equals -19.
Step-by-step explanation:
You have to plug in the numbers where the variables are, so it would be -8-(-11).
Whats the diameter?
1/8(3.14) = 0.3925