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3 years ago

12. A rectangle PQRS is congruent to rectangle JKLM. If the area of rectangle PQRS is

Mathematics

1 answer:

Anton [14]3 years ago

5 0

Answer:

Step-by-step explanation:

The same if the rectangles are congruent. Orientation won't matter.

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Is the absolute value of ab equal to the absolute value of a divided the absolute value of b?

Serggg [28]

They can be equal if the absolute value of b is 1.

3 0

3 years ago

Read 2 more answers

PLEASE HELP ME! I REALLY NEED IT! <br> Write the equation of the line in point-slope form.

kolezko [41]

Answer:

y=-x/3-8

Step-by-step explanation:

First we find 2 points:

(0,-8) and (6,-10)

then substitute in y=ax+b equation

-8=0a+b, b=-8

-10=6a-8

a= -1/3

6 0

3 years ago

Image for last question look at my last

SVETLANKA909090 [29]

Answer:

Part A: 12.5 cm

Part B: 0.8 km

Step-by-step explanation:

Map scale problems can be solved with proportions.

Part A

5 cm / 2 km = x cm / 5 km

5/2 = x/5

2x = 25

x = 12.5

Answer: 12.5 cm

Part B

5 cm / 2 km = 2 cm / x km

5/2 = 2/x

5x = 4

x = 4/5

x = 0.8

Answer: 0.8 km

6 0

2 years ago

I need your help guys please

myrzilka [38]

1) 2x+14=x+18
2x=x+4
x=4

2) 9y-2=3y+10
9y=3y+12
6y=12
y=2

3) 2*(2[4]+14) + (9[2]-2)

4) 32/2=16

5) 11*2=22

4 0

2 years ago

Will give brainliest! pts to the correct answer! Are quadratic equations already in rectangular form? I'm asked to eliminate th

Semmy [17]

$\bf x(t)=0.5t^2+0.4t-87.30\implies x(t)=\cfrac{1}{2}t^2+\cfrac{2}{5}t-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left( t^2+\cfrac{4}{5}t+\boxed{?}^2 \right)-\cfrac{873}{10}$

so, as you already know, we'll borrow from our good friend Mr Zero, 0, to get that missing value for the perfect square trinomial,

$\bf x=\cfrac{1}{2}\left[ t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2-\left( \cfrac{2}{5} \right)^2 \right]-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\cfrac{4}{25}-\cfrac{4}{25} \right]-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2\right]-\cfrac{2}{25}-\cfrac{873}{10}
\\\\\\
x=\cfrac{1}{2}\left[t^2+\cfrac{4}{5}t+\left( \cfrac{2}{5} \right)^2\right]-\cfrac{4369}{50}$

$\bf x=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2-\cfrac{4369}{50}\implies x+\cfrac{4369}{50}=\cfrac{1}{2}\left( t+\frac{2}{5} \right)^2
\\\\\\
2x+\cfrac{4369}{25}=\left( t+\frac{2}{5} \right)^2\implies \sqrt{2x+\cfrac{4369}{25}}=t+\cfrac{2}{5}
\\\\\\
\sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5}=t$

$\bf -------------------------------\\\\
y(t)=0.4t^2+0.1t+29.44\implies y=\cfrac{2}{5}t^2+\cfrac{1}{10}t+\cfrac{736}{25}
\\\\\\
y=\cfrac{2}{5}\left( \sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5} \right)^2+\cfrac{1}{10}\left( \sqrt{2x+\cfrac{4369}{25}}-\cfrac{2}{5} \right)+\cfrac{736}{25}$

4 0

3 years ago