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Sidana [21]
2 years ago
12

I need your help guys please ​

Mathematics
1 answer:
myrzilka [38]2 years ago
4 0
1) 2x+14=x+18
2x=x+4
x=4

2) 9y-2=3y+10
9y=3y+12
6y=12
y=2

3) 2*(2[4]+14) + (9[2]-2)

4) 32/2=16

5) 11*2=22
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Find the length of UC? Please help
Roman55 [17]

Answer:

The choose C. 18

Step-by-step explanation:

UC —> 105+82=187 —> 96+22+51=169 —> 187–169=18

I hope I helped you^_^

7 0
2 years ago
Evaluate:<br> g(x) = 3•2x+2 + 3<br> g(3)
Studentka2010 [4]

Answer:23

Step-by-step explanation:

3·2(3)+2+3

=3·6+2+3

=23

6 0
3 years ago
Write a recursive formula for an, the nth term of the sequence 3, -4, -11
yKpoI14uk [10]

Answer:

, 12, 48, 192...

a. Write a recursive formula for the nth term of the sequence

Ans: a(n+1) = 4*a(n)

------------------------------

b. Write a general formula for the nth term of the sequence

a(n) = 3*4^(n-1)

--------------

c. Calculate S10 for this sequence

Geometric sequence with a(1) = 3 and r = 4

----?

Step-by-step explanation:

8 0
3 years ago
Convert the expression to radical form. 8(1/2)x(1/2)y(3/4) A) 8xy3 B) 2xy 2xy2 C) 2x2y3 D) 2 4x2y3
UNO [17]
Your answer should be B : ) 




I hope this helps!





please mark this as the brainliest 
7 0
3 years ago
The population of a town 4 years ago was 50,000
tino4ka555 [31]

Answer:

population will be 79806.

Step-by-step explanation:

Population of a town 4 years ago  was 50,000

Population of town had grown exponentially and present population is 63,124.

So the formula of the population growth will be

A_{n}=A_{o}(r)^{n-1}

Where A_{n} = Final population n = number of years.

           A_{o} = Initial population

           r = rate of increase in population per year.

so  63124 = 50,000 (r)^{4-1}

r^{3}=\frac{63124}{50000}= 1.26428

r=(1.26428)^{\frac{1}{3} }

= 1.0813

Now we have to find the population after 4 years from now.

A_{n} =  63124(1.08)^{4-1}

       =  63124(1.08)^{3}

       = 63124 × 1.264

       = 79806

Therefore, after 4 years from now population will be 79806.

8 0
3 years ago
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