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3 years ago

What is the perimeter of a triangle whose sides are 4x, 3x+5, and 9-x?

Mathematics

1 answer:

Komok [63]3 years ago

3 0

Answer:

if these expression represent side lengths, then you simply add those three expressions, and that's the perimeter.

Step-by-step explanation:

I explore this idea a bit. obviously x < 5 (because 5-x has to be positive.

2x-5 > 0 is a requirement, also, so x > 2.5 is required.

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3 years ago

Find the volume of the figure. Round to the

Elodia [21]

Answer:

1,286.1 units is the answer

Step-by-step explanation:

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3 years ago

Is f (x)=4/x a exponential function

maks197457 [2]

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3 years ago

Read 2 more answers

Which expression is equivalent to log Subscript c Baseline StartFraction x squared minus 1 Over 5 x EndFraction?

Harrizon [31]

The equivalent expression of $\log_c(\frac{x^2 - 1}{5x})$ is $\log_c(x^2 - 1) - \log_c(5x)$

<h3>How to determine the equivalent expression?</h3>

The logarithmic expression is given as:

$\log_c(\frac{x^2 - 1}{5x})$

The law of logarithm states that:

log(a) - log(b) = log(a/b)

This means that the expression can be split as:

$\log_c(\frac{x^2 - 1}{5x}) = \log_c(x^2 - 1) - \log_c(5x)$

Hence, the equivalent expression of $\log_c(\frac{x^2 - 1}{5x})$ is $\log_c(x^2 - 1) - \log_c(5x)$

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2 years ago

Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,

Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j} = {(1,0), (0,1)}

is a base in $\mathbb{R}^2$

and F is linear, then

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

3 0

3 years ago