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igomit [66]
3 years ago
8

What is The prime factorization of is 24 × 5.

Mathematics
2 answers:
WARRIOR [948]3 years ago
6 0

Answer: 24

Step-by-step explanation:2x2x2x3 is 24

Anna [14]3 years ago
4 0

Answer:

The prime factorization of the number 24 is 2 × 2 × 2 × 3.

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don't know how to do this kind of math anymore so if someone could me it would be really great 2.54 x .12000 =
Reptile [31]

Answer:

2.54*0.12=0.3048

5 0
3 years ago
Calculate the state income tax owed on a $90,000<br> per year salary.<br> tax = $[?]
lakkis [162]

Answer:

$4918

Step-by-step explanation:

first income must be divided according to tax bracket

2% tax on first 3000 income= 2% of $3000=$60

3% tax on income after first 3000 but upto 5000= 5000-3000= $2000

=3% of 2000= $60

5% tax on income after second 5000 but upto 12000= 17000-5000

=12000 5% of $12000= $600

Lastly, 5.75% income over 17000=

90000-17000= $73000 so, 5.75 % of 73000= $4197.5

tax= $60+60+600+4197.5

= $4917.5

= $4918

6 0
3 years ago
Can someone help me number 4 only thanks :)
Elanso [62]
22 boxes still need to be given out
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3 years ago
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A triangle with side lengths of 32, 60 and 68 is a right triangle?<br> true or false
Troyanec [42]
I believe that it would come out to become true
5 0
4 years ago
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Prove that the diagonals of a parallelogram bisect each other​
Nady [450]

Answer:

[ See the attached picture ]

The diagonals of a parallelogram bisect each other.

✧ Given : ABCD is a parallelogram. Diagonals AC and BD intersect at O.

✺ To prove : AC and BD bisect each other at O , i.e AO = OC and BO = OD.

Proof :\begin{array}{ |c| c |  c |  } \hline \tt{SN}& \tt{STATEMENTS} & \tt{REASONS}\\ \hline 1& \sf{In  \: \triangle ^{s}  \:AOB \: and \: COD  } \\  \sf{(i)}&  \sf{ \angle \: OAB =  \angle \: OCD\: (A)}& \sf{AB \parallel \: DC \: and \: alternate \: angles} \\  \sf{(ii)} &\sf{AB = DC(S)}& \sf{Opposite \: sides \: of \: a \: parallelogram} \\  \sf{(iii)} &\sf{ \angle \: OBA=  \angle \: ODC(A)} &\sf{AB \parallel \:DC \: and \: alternate \: angles} \\  \sf{(iv)}& \sf{ \triangle \:AOB\cong \triangle \: COD}& \sf{A.S.A \: axiom}\\ \hline 2.& \sf{AO = OC \: and \: BO = OD}& \sf{Corresponding \: sides \: of \: congruent \: triangle}\\ \hline 3.& \sf{AC \: and \: BD \: bisect \: each \: other \: at \: O}& \sf{From \: statement \: (2)}\\ \\ \hline\end{array}.          Proved ✔

♕ And we're done! Hurrayyy! ;)

# STUDY HARD! So, Tomorrow you can answer people like this , " Dude , I just bought this expensive mobile phone but it is not that expensive for me" [ - Unknown ] :P

☄ Hope I helped! ♡

☃ Let me know if you have any questions! ♪

\underbrace{ \overbrace  {\mathfrak{Carry \: On \: Learning}}} ☂

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5 0
3 years ago
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