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Masja [62]
3 years ago
13

Weegy if one angle of a rhombus is 35 what are the remaining three angles

Mathematics
1 answer:
Assoli18 [71]3 years ago
7 0
Rhombus, <span>opposite angles are congruent
One angle is 35 so the opposite angle will be 35 also.

Sum of interior angles in a rhombus equal 360

360 - 35 - 35 = 290

290/2 = 145 (The other two angles will be congruent)

Answer:
The remaining three angles will be 35</span>°<span>, 145</span>°<span>, 145</span>°<span>


</span>
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Answer:

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Step-by-step explanation:

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How much simple interest would 1000 earn in 275 days at an interest rate of 4.21%
nikitadnepr [17]
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3 years ago
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5 0
3 years ago
MN is a diameter of a circle with centre ' O ' . If BD = CD , prove that ∠OAD = ∠OCD
Varvara68 [4.7K]

Answer:

\sf \: Proved \: \angle \: OAD  \:  =  \angle \: OCD

Step-by-step explanation:

<em>Given:</em>

Mn is diameter of circle having centre O

and BD = OD,

<em><u>To prove that:</u></em>

<u>\angle \: OAD  \:  =  \angle \: OCD</u>

<em>Solution:</em>

Join the points O and B and draw OB,

On joining the line,

in ∆OCD and ∆OBD,

OC =OB → (Radius of same circle)

BD =CD → (from given)

OD =OD → (Common side in both the triangles)

Hence ∆OCD and ∆OBD are congruent from SSS property.

so we can say that,

\angle \: OBD  \:  =  \angle \: OCD

Consider above prove as statement A

Corresponding angles of congruent traingle.

in ∆ OAB,

OA = OB (radius of same circle)

hence ∆OAB is an isosceles traingle.

We know that opposite angle of isosceles traingle are always equal. hence,

\angle \: OBD  \:  =  \angle \: OAB \\ \angle \: OAB  \:  =  \angle \: OAD (same \: angles) \\ \angle \: OBD  \:  =  \angle \: OAD

Consider above prove as statement B

From Statement A & B we can say that

\angle \: OAD  \:  =  \angle \: OCD

<em>Thanks for joining brainly community!</em>

5 0
2 years ago
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