Answer: Structured compensation program
Explanation: In a structured compensation program the company structures the pay of employees on the basis of a predetermined criteria. The abilities needed to get promotion in such structure could be fixed on the basis of time period served or any other such criteria.
In the given case, Jamie gets promotion at every stage by passing a certain test. Thus, we can conclude that the company is performing structured program.
Answer:
Amount of cash flow will be $2328
So option (B) will be the correct answer
Explanation:
We have given total merchandise = $4000
And return merchandise = $1600
Here 
means if Sheridan Company makes the payment within 10 days then he will get discount of 3 % as in the question he makes the payment within 10 days so he will will get 3 % discount
Now amount of cash received = total merchandise - return merchandise
= $4000 - $1600 = $2400
Now discount is 3 %
So after discount amount received 
So option (B) will be the correct answer
Answer:
Instructions are listed below
Explanation:
Giving the following information:
The high-low method involves taking the highest level of activity and the lowest level of activity and comparing the total costs at each level.
Mountain has recorded the following for the past nine months:
January:
Number of Cavities= 375
Total cost= $5,300
February:
Number of Cavities 500
TC= 5,850
March
Number of Cavities 350
TC= 5,200
April
Number of Cavities 600
TC=6,250
May
Number of Cavities 325
TC= 5,150
June
Number of Cavities 475
TC= 5,700
July
Number of Cavities 525
TC= 6,100
August
Number of Cavities 575
TC= 6,300
September
Number of Cavities 450
TC= 5,550
A) Variable cost= (Highest activity cost - lowest activity cost) / (Highest activity units - lowest activity units)
Variable cost= (6300 - 5150) / (600 - 325)= 4.18 per unit
Fixed cost= HACost - (variable cost per unit * HAUnits)= 6300 - (4.18*600)= 3792
Fixed cost= LACost - (variable cost per unit* LAUnits)= 5150 - (4.18*325)= 3792
B) Q= 400
Total cost= 3792 + 4.18*400= $5464
Solution:
Given Information,
Heat input is ( 
) = 5.5 × 
Btu/h
Combustion efficiency of the boiler (
) = 0.7
Combustion efficiency after turn up (
) = 0.8
Operation Hour (t) = 5200h
Unit cost (c) = 
Calculate heat output from the boiler 
= x
= 5.5 x x 0.7
= 3.85 x Btu/h
Calculate the heat input to the boiler after the tune-up
= / 
= 3.85 x / 0.8
= 4.8125 x Btu/h
Calculate the saved energy after the tune-up
= -
= 5.5 x - 4.8125 x Btu/h
= 0.6875 x Btu/h
Calculate the annual energy saving ( 
)
= x t
= ( 0.6875 x Btu/h ) ( 5200 hr/yr)
= 3575 x Btu/h
Calculate the annual cost saving
Annual cost saving = 
x Unit cost
= 3575 x Btu/h x
= 82225
