The age of Blain is 23 years old
<h3><u>Solution:</u></h3>
Let the age of Blain be "a" and age of Jillian be "b"
Given that Blain is two years older than three times Jillians age
So we can frame a equation as:
age of blain = 2 + 3(age of Jillian)
a = 2 + 3b ----- eqn 1
Also given that Jillian is also 16 years younger than Blain
Age of Jillain = Age of Blain - 16
b = a - 16 ---- eqn 2
Substitute eqn 2 in eqn 1
a = 2 + 3(a - 16)
a = 2 + 3a - 48
a - 3a = -46
-2a = -46
a = 23
Thus the age of Blain is 23 years old
+ 6 +
= 18
First, simplify
to
/ Your problem should look like:
+ 6 +
= 18
Second, simplify
to
/ Your problem should look like:
+ 6 +
= 18
Third, simplify
+ 6 +
to
+ 6 / Your problem should look like:
+ 6 = 18
Fourth, regroup terms. / Your problem should look like: 6 -
= 18
Fifth, multiply both sides by 7. / Your problem should look like: 42 - x = 126
Sixth, subtract 42 from both sides. / Your problem should look like: -x = 126 - 42
Seventh, simplify 126 - 42 to 84. / Your problem should look like: -x = 84
Eighth, multiply both sides by -1. / Your problem should look like: x = -84
Answer:
x = -84
Answer:
Step-by-step explanation:
Answer:
4/18
Step-by-step explanation:
Answer:
10x^3 - 2x^2 -7
Step-by-step explanation:
To subtract polynomials, you want to subtract the biggest exponent from the first polynomial to the second
so 6x^3 + 4x^3 and that would be 10x^3
then -3x^2 + x^2 and the negative is larger so it would be -2x^2
and finally -2 + -5 and that is -7
hope this helps! :)
