Answer: 90% confidence interval is; ( - 0.0516, 0.3752 )
Step-by-step explanation:
Given the data in the question;
n1 = 72, n2 = 17
P1 = 54 / 72 = 0.75
P2 = 10 / 17 = 0.5882
so
P_good = 0.75
P_bad = 0.5882
standard ERRROR will be;
SE = √[(0.75×(1-0.75)/72) + (0.5882×(1-0.5882)/17)]
SE = √( 0.002604 + 0.01424)
SE = 0.12978
given confidence interval = 90%
significance level a = (1 - 90/100) = 0.1, |Z( 0.1/2=0.05)| = 1.645 { from standard normal table}
so
93% CI is;
(0.75 - 0.5882) - 1.645×0.12978 <P_good - P_bad< (0.75 - 0.5882) + 1.645×0.12978
⇒0.1618 - 0.2134 <P_good - P_bad< 0.1618 + 0.2134
⇒ - 0.0516 <P_good - P_bad< 0.3752
Therefore 90% confidence interval is; ( - 0.0516, 0.3752 )
Answer:
Step-by-step explanation:
p(headache) = 0.45
p(headache | taking a vitamin) = 0.15/0.50 = 0.30
The two probabilities <em>are not equal</em>.
1/5 (18-11) I believe this is what you mean?
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Answer:
Please check the explanation.
Step-by-step explanation:
- As we know that the values in the table represent a function only if there there is only 1 input for every output.
Given the table 1
x y
-12 2
-10 10
0 -2
5 -6
8 -11
15 -15
From the table, it is clear that for each input there exists a unique output.
i.e.
According to the given table,
y = 2 at x=-12
y = 10 at x=-1
0
y = -1 at x=0
y = -11 at x=8
y = -15 at x=15
From the table, it is clear that for each input x, it has a unique output y.
Hence, table 1 is a function.
Given the table 2
x y
9 -18
-20 0
-6 1
-17 16
9 17
11 19
This table does not produce a function, because the input x=9 produces two outputs.
i.e.
at x = 9, the y = -18
at x = 9, the y = 17
Therefore, the table 2 does not represent a function.