Which graph represents exponential decay?

Randomly take 4 cards from a deck of 52 cards, find the probability that the 4 cards are all aces

kompoz [17]

You would divide the number of aces in a deck, which is 4, ny 52 which will give you about 0.0769. As a percentage it will be 7.69%. Round it off to 7.7% if you like. It’s either 7.7% it 7.69%.

3 0

3 years ago

22. Which equation has solutions of -2 and 3?

tatyana61 [14]

Answer:

B. y=x²-x-6

Step-by-step explanation:

Consider the product ...

0 = (x -a)(x -b) = x² -(a+b)x +ab

This equation has solutions x=a and x=b. You will note that ...

the constant is the product of the solutions (ab)
the coefficient of x is the opposite of their sum (-(a+b))

For solutions of -2 and 3, the constant will be (-2)(3) = -6. This eliminates choices C and D.

The sum of the solutions is -2+3 = 1, so the coefficient of x is -1, matching choice B.

5 0

3 years ago

Will the second showing be over by 6:30

const2013 [10]

Yes it will isnt that amazing now you can do more stuff.

3 0

3 years ago

(a^3 b^12 c^2) * (a^5 c^2) * (b^5 c^4)^0

trapecia [35]

Step-by-step explanation:

$= ( {a}^{3} {b}^{12} {c}^{2} ) \times ( {a}^{5} {c}^{2} ) \times ( {b}^{5} {c}^{4} ) {}^{0}$

$= {a}^{3 + 5} {b}^{12} {c}^{2 + 2}$

$= {a}^{8} {b}^{12} {c}^{4}$

Option D

3 0

3 years ago

Suppose that the distribution of typing speed in words per minute (wpm) for experienced typists using a new type of split keyboa

KengaRu [80]

Answer:

a. 0.5 or 50%

b. 0.496 or 49.6%

c. 0.8185 or 81.85%

d. Yes, it would be just 0.0013 or 0.13% of probability to find a typist whose speed exceeds 105 wpm

e. 0.0252 or 2.52%

f. The qualifying speed would be 47.4 wpm.

Step-by-step explanation:

a. Let's find the z-score this way:

μ = 60 σ= 15

z-score = (x - μ)/σ

z-score = (60 - 60)/15

z-score = 0

Now, let's calculate the p value for z-score = 0, using the z-table:

p (z=0) = 0.5 or 50%

b. z-score = (x - μ)/σ

z-score = (59.9 - 60)/15

z-score = -0.01

Now, let's calculate the p value for z-score = -.0.01, using the z-table:

p (z = -0.01) = 0.496 or 49.6%

If the question were less or equal than 60, a and b would have the same answer. But in this case, the question is "less than 60 wpm".

c.

z-score = (x - μ)/σ

z-score = (45 - 60)/15

z-score = - 1

Now, let's calculate the p value for z-score = -1, using the z-table:

p (z = -1) = 0.1587

z-score = (x - μ)/σ

z-score = (90 - 60)/15

z-score = 2

Now, let's calculate the p value for z-score = 2, using the z-table:

p (z = 2) = 0.9772

In consequence,

p (-1 ≤ z ≤ 2) = 0.9772 - 0.1587 = 0.8185 or 81.85%

d. z-score = (x - μ)/σ

z-score = (105 - 60)/15

z-score = 3

Now, let's calculate the p value for z-score = 3, using the z-table:

p (z = 3) = 0.9987

In consequence,

p (z > 3) = 1 - 0.9987 = 0.0013

Yes, it would be just a 0.13% of probability to find a typist whose speed exceeds 105 wpm.

e. z-score = (x - μ)/σ

z-score = (75 - 60)/15

z-score = 1

Now, let's calculate the p value for z-score = 1, using the z-table:

p (z = 1) = 0.8413

In consequence,

p (z > 1) = 1 - 0.8413 = 0.1587

and if the two typists are independently selected, then

p = 0.1587 * 0.1587

p = 0.0252 or 2.52%

f. p = 0.2, using the z-table, the z-score is -0.84, then:

z-score = (x - μ)/σ

-0.84 = (x - 60)/15

-12.6 = x - 60

-x = -60 + 12.6

-x = - 47.4

x = 47.4

The qualifying speed would be 47.4 wpm.

8 0

3 years ago