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makvit [3.9K]
3 years ago
15

A forest covers 33,000 acres. A survey finds that 0.8% of a forest is old-growth-tree. How many acres of old-growth-trees are th

ere?

Mathematics
1 answer:
natali 33 [55]3 years ago
5 0

Answer:

264 acres

Step-by-step explanation:

Since 33,000 acres is 100%, 330 acres is 1% because 33000 acres divided by 100 is 330 acres. Then if 330 acres is 1%, 33 acres is 0.1% because 330 acres divided by 10 is 33 acres. 1 divided by 10 is 0.1.

Next 33 acres times 8 because 0.8% is eight times bigger than 0.01%. This equals to 264 acres.

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30 points and brainliest help me out please. 5th grade
Tatiana [17]

Answer:

Step-by-step explanation:

a,a, and a

8 0
3 years ago
The regression equation for predicting number of speeding tickets (Y) from information about driver age (X) is Y = -.065(X) + 5.
ivolga24 [154]

Answer:

c. 4.27

Step-by-step explanation:

We have been given the regression equation of for predicting number of speeding tickets (Y) from information about driver age (X) as Y=-0.065(X)+5.57.

To find the predicted number of tickets for a twenty-year-old, we will substitute X=20 in our given equation.

Y=-0.065(20)+5.57

Y=-1.3+5.57

Y=4.27

Therefore, the predicted number of tickets for a twenty-year-old would be 4.27 tickets.

6 0
4 years ago
I don't understand how to do this problem.
Delicious77 [7]
Answers: 

x = 4
EF = 14
CF = 7
EC = 7

-------------------------------------------------------------
-------------------------------------------------------------

Work Shown:

C is the midpoint of segment EF. This means that EC = CF. In other words, the two pieces are congruent. 

Use substitution and solve for x
EC = CF
5x-13 = 3x-5
5x-13+13 = 3x-5+13
5x = 3x+8
5x-3x = 3x+8-3x
2x = 8
2x/2 = 8/2
x = 4

Now that we know that x = 4, we can use this to find EC and CF

Let's compute EC
EC = 5x - 13
EC = 5*x - 13
EC = 5*4 - 13 ... replace x with 4
EC = 20 - 13
EC = 7

Let's compute CF
CF = 3x - 5
CF = 3*x - 5
CF = 3*4 - 5 ... replace x with 4
CF = 12 - 5
CF = 7

As expected, EC = CF (both are 7 units long).

By the segment addition postulate, we can say EC+CF = EF

EC+CF = EF
EF = EC+CF
EF = 7+7
EF = 14
8 0
3 years ago
A circle has a radius of 3. An arc in this circle has a central angle of 20
ki77a [65]

A circle has a radius of 3 An arc in this circle has a central angle of 20 what is the length of the arc

8 0
4 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 50 ft deep. The bucket is f
Natalija [7]

Answer:

Therefore total work done =2050 ft-lb

Step-by-step explanation:

Given that, a bucket are used to drawn water from a well that is 50 ft deep.

(1)

Work done = Force×displacement.

Work done to pull the bucket is

= Weight of the bucket × displacement

=(6×50) ft-lb

=300 ft-lb

(2)

The bucket fill with 40 lb of water and is pulled up at a rate of 2ft/s, but leaks out of a hole in the bucket at a rate of 0.2 lb/s.

Since the well is 50 ft deep.

It takes =\frac{50ft}{2ft/s} =25 s to pull the bucket at the top of the well.

After 25 s it lost (25×0.2)lb =5 lb water.

So the remaining water is = (40-5) lb= 35 lb

Let y is distance above the original depth of 50 ft.

When y=50 ft, weight of the bucket= 40 lb,when y=0 weight of the bucket= 35 lb

The slope of the of water leakage is

=\frac{40-35}{50-0}

=\frac{1}{10}

The bucket holds (40-\frac1{10}y) lb of water when it is y ft above the original depth.

Work done to pull the water in the bucket is

=\int _0^{50}(40-\frac1{10}y)dy

=[40y- \frac1{10}y^2]_0^{50}

=[(40\times 50)-\frac1{10}(50)^2]-[(40\times 0)-\frac1{10}(0)^2]

=1750 ft-lb

Therefore total work done

=Work done to pull the bucket+Work done to pull the water in the bucket

=(300+1750) ft-lb

=2050 ft-lb

5 0
3 years ago
Read 2 more answers
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