Answer:
Explanation:
The Hexa-decimal numbers have base 16 and includes numbers:
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E and F
The given steps are performed to convert a decimal number to hexa-decimal number, here to convert decimal number 35 to hexa-decimal number:
- Divide 35 by 16
- Note the remainder, r which is 3 here and quotient which is 2
- Again divide 2 (quotient) by 16 and note the remainder, r' which is 2 and quotient is 0
- We will stop here as the quotient is now 0. Usually division by 16 is repeated until we get quotient = 0
- Now arrange the remainder in reverse order to get the hexa-decimal number as r'r
- The hexa-decimal number is
Answer:
The correct option is pane.setOnMouseClicked((e) -> System.out.println(e.getX() + ", " + e.getY()));
Explanation:
As the complete question is not provided, the complete question is attached herewith.
In order to handle the underlined location the way is to get the position using the MouseClicked event which will be activated when the mouse is clicked and then the values of X and Y position will be printed.
pane.setOnMouseClicked((e) -> System.out.println(e.getX() + ", " + e.getY()));
The other options are not correct as the handle used in them is not defined for this purpose.
A driver for that hardware specific task. Like Nvidia makes GPU's so they also make GPU drivers
Answer:
The display will be 17.
Explanation:
Tracing through the program:
At first, math is called and sent 1 and 2 - so 1 is stored to ans1 and 2 is stored to ans2.
If the user inputs 3 for a and 4 for b, the program then calls function math2 and passed values of 3 and 4.
So now inside of math2, 3 is stored to res1 and 4 is stored to res3. Inside of this function, res1 and res2 are added together - so then 7 is stored to d and then returned back to the original function.
So now 7 was stored back to the variable c. Then a and ans1 are added together (3 + 1 = 4) and b and ans2 are added together (4 + 2 = 6). Each of these values are stored back to e and f.
Then those values, e and f (4 and 6) are again sent to math2, which simply adds the values together and returns it back to the function. So 10 is sent back to math and stored to the value of g.
Then c (7) and g (10) are added together and displayed.
Answer:
I would pick A B and D to be my answer