Level 5 ( Full Driving Automation ) Level 5 cars won't even have steering wheels or acceleration / braking pedals . They will be free from geofencing , able to go anywhere and do anything that an experienced human driver can do .
Pls follow me and Mark as brainlest!!! :-)
Answer:
#include <iostream>
#include <cstring>
using namespace std;
bool isAPalindrome(char* palindrome);
int main()
{
char palindrome[30];
bool palindrome_check;
cout << "Please enter an word or phrase.\n";
cin.getline(palindrome, 30);
palindrome_check = isAPalindrome(palindrome);
if (palindrome_check = true)
{
cout << "Input is a palindrome\n";
}
else
{
cout << "Inputis not a palindrome\n;";
}
system("pause");
return 0;
}
bool isAPalindrome(char* palindrome)
{
char* front;
char* rear;
front = palindrome;// starts at the left side of the c string
rear = (palindrome + strlen(palindrome)) - 1;//starts at the right side of the c-string. adds the c string plus the incriment value of s
while (front <= rear)
{
if (front = rear)
{
front++;
rear--;
}
else
{
return false;
}
}
return true;
}
Answer: share information and collaborate with a select group of outside organizations or individuals.
Explanation:
When a company uses an intranet, it is for the purpose of sharing information within the company so in the same vein, an extranet is done to share information with entities outside the company be it people or organizations.
For information to be shared, the other companies and organizations need to have the means and authorization to join the extranet. Extranets are very useful as they enable collaboration across vast distances thereby increasing productivity.
#include <stdio.h>
struct student {
char firstName[50];
int roll;
float marks;
} s[5];
int main() {
int i;
printf("Enter information of students:\n");
// storing information
for (i = 0; i < 5; ++i) {
s[i].roll = i + 1;
printf("\nFor roll number%d,\n", s[i].roll);
printf("Enter first name: ");
scanf("%s", s[i].firstName);
printf("Enter marks: ");
scanf("%f", &s[i].marks);
}
printf("Displaying Information:\n\n");
// displaying information
for (i = 0; i < 5; ++i) {
printf("\nRoll number: %d\n", i + 1);
printf("First name: ");
puts(s[i].firstName);
printf("Marks: %.1f", s[i].marks);
printf("\n");
}
return 0;
}
#◌⑅⃝●♡⋆♡Nåmřāthā ♡⋆♡●⑅◌
Answer:
B
Explanation:
took the test on egdenuity
