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2 years ago

Simplify the expression 3(× -6) + (4× + 12) -6×

Mathematics

1 answer:

forsale [732]2 years ago

5 0

Answer:

I messed up and forgot the six at the end dont put that answer as your answer sorry

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2 years ago

3) Solve each equation using the quadratic formula. Show<br> a. x2 – 3x – 10 = 0

Naya [18.7K]

Answer:

Step-by-step explanation:

The quadratic formula of a quadratic equation

$ax^2+bx+c=0\\\\\text{If}\ b^2-4ac>0\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$\text{If}\ b^2-4ac=0\ \text{then the equation has one solution}\ x=\dfrac{-b}{2a}$

$\text{If}\ b^2-4ac$

We have:

$x^2-3x-10=0\to a=1,\ b=-3,\ c=-10\\\\b^2-4ac=(-3)^2-4(1)(-10)=9+40=49>0\\\\x=\dfrac{-(-3)\pm\sqrt{49}}{2(1)}=\dfrac{3\pm7}{2}\\\\x=\dfrac{3-7}{2}=\dfrac{-4}{2}=-2\\or\\x=\dfrac{3+7}{2}=\dfrac{10}{2}=5$

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2 years ago

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vovangra [49]

Answer:

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Step-by-step explanation:

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2 years ago

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sleet_krkn [62]

Answer:

x = 2.8 units

Step-by-step explanation:

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2 years ago

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Which equation has x = –6 as the solution?

olya-2409 [2.1K]

Answer:

The equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. $\log _3\left(-2x-3\right)=2$ has x = –6 as the solution.

Step-by-step explanation:

<u>Checking the equation</u>

log Subscript 3 Baseline (negative 2 x minus 3) = 2

Writing in algebraic expression

$\log _3\left(-2x-3\right)=2$

Use the logarithmic definition

$\mathrm{If}\:\log _a\left(b\right)=c\:\mathrm{then}\:b=a^c$

$\log _3\left(-2x-3\right)=2\quad \Rightarrow \quad \:-2x-3=3^2$

$-2x-3=3^2$

$-2x-3=9$

$-2x=12$

$\mathrm{Divide\:both\:sides\:by\:}-2$

$\frac{-2x}{-2}=\frac{12}{-2}$

$x=-6$

Therefore, the equation 'log Subscript 3 Baseline (negative 2 x minus 3) = 2' i.e. $\log _3\left(-2x-3\right)=2$ has x = –6 as the solution.

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3 years ago

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