Answer:
A. It is symmetric and has no gaps.
Step-by-step explanation:
Given
See attachment for dot plot
Required
Select the true statement
From the attached plot, we can see that
Since (1) all bell shaped distribution are symmetric and (2) there is no gap between the dataset, <em>then (a) is correct.</em>
Answer:
see explanation
Step-by-step explanation:
If we consider the differences between consecutive terms, that is
-
=
1 -
=
1 - 1
=
To obtain the next term in the pattern add to the previous term.
batches = 5 ⇒ milk = 1 +
= 1
batches = 6 ⇒ milk = 1 +
= 2
The values of a and b are a = 33% and b = 43% ⇒ last answer
Step-by-step explanation:
The venn-diagram contains:
The table:
→ Band : blue : N.b : total
→ gold : 16% : a : 49%
→ N.g : b : 8% : 51%
→ Total : 59% : 41% : 100%
We need to find the values of a and b
From the table
16% represents the percentage of blue and gold uniforms (2nd row with 2nd column)
From venn-diagram
The common part of blue and gold label with 12 (overlap of two circles)
∴ 16% of the total number of students = 12
∵ 16% × x = 12
∴ × x = 12
∴ 0.16 x = 12
- Divide both sides by 0.16
∴ x = 75
∵ x represents the total number of students
∴ The total number of students were asked is 75
From the table
b represents the percentage of blue but not gold uniforms (3rd row and 2nd column)
From venn-diagram
The part that has blue and not gold labeled with 32 (the part of the blue circle not in the gold circle)
∴ 32 of the total number of students like the blue but not gold
- Divide 32 by the total 75 , then multiply the quotient by 100%
to find the percentage of blue but not gold
∴ b = × 100% = 42.6666%
∴ b ≅ 43%
From the table
a represents the percentage of gold nut not blue uniforms (2nd row and 3rd column)
From venn-diagram
The part that has gold and not blue labeled with 25 (the part of the gold circle not in the blue circle)
∴ 25 of the total number of students like the gold but not blue
- Divide 25 by the total 75 , then multiply the quotient by 100%
to find the percentage of gold but not blue
∴ a = × 100% = 33.3333%
∴ a ≅ 33%
The values of a and b are a = 33% and b = 43%
To check your answer complete the table you will find the total of it is 100% ( for the columns 16% + 43% = 59% , 33% + 8% = 41% , then 59% + 41% = 100%, for the rows 16% + 33% = 49% , 43% + 8% = 51% , then 49% + 51% = 100%)
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Answer:
(a) As time increases, the amount of water in the pool increases.
11 gallons per minute
(b) 65 gallons
Step-by-step explanation:
From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.
We are told that Ann adds water at a constant rate. Therefore, this can be modeled as a linear function.
The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).
Choose 2 ordered pairs from the table:
Input these into the slope formula:
Therefore, the rate at which the water in the pool is increasing is:
<u>11 gallons per minute</u>
To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:
When Ann had added no water, x = 0. Therefore,
So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.
Answer:
The quantity of acid in the solution is 47.1 ml
Step-by-step explanation:
Given as :
The quantity of solution of acid and water = 357 millimeters
The percentage of acid in the solution = 13.2 %
Let the quantity of acid in the solution = x ml
<u>So, According to question </u>
13.2 % of the total quantity of acid in the solution = x
I.e x = 13.2 % × 357
Or, x = × 357
Or, x = 0.132 × 357
∴ x = 47.124 millimeters
So , The quantity of acid = 47.1 ml
Hence The quantity of acid in the solution is 47.124 ml Answer