Answer:
Answers are in the explanation.
Explanation:
- The half‑life of A increases as the initial concentration of A decreases. order: <em>2. </em>In the half-life of second-order reactions, the half-life is inversely proportional to initial concentration.
- A three‑fold increase in the initial concentration of A leads to a nine‑fold increase in the initial rate. order: <em>2. </em>The rate law of second-order is: rate = k[A]²
- A three‑fold increase in the initial concentration of A leads to a 1.73‑fold increase in the initial rate. order: <em>1/2. </em>The rate law for this reaction is: rate = k √[A]
- The time required for [A] to decrease from [A]₀ to [A]₀/2 is equal to the time required for [A] to decrease from [A]₀/2 to [A]₀/4. order: <em>1. </em>The concentration-time equation for first-order reaction is: ln[A] = ln[A]₀ - kt. That means the [A] decreasing logarithmically.
- The rate of decrease of [A] is a constant. order: <em>0. </em>The rate law is: rate = k -<em>where k is a constant-</em>
It's a natural element because it appears on earth
Antiemetics
Antiemetics will most likely be given to chemotherapy patients to treat nausea and vomiting, and up to three antiemetics may be used. The most common serotonin receptor blockers are:
Zofran (ondansetron)
Emend (aprepitant)
Aloxi (palonosetron)
Compazine (prochlorperazine)
Some patients experience nausea and vomiting prior to the infusion. An anti-anxiety medication such as Ativan may be beneficial. A suppository can be used in patients who are already vomiting. Nausea and vomiting can occur before, during, or after chemo treatment. Therefore, to combat the most common adverse effects of chemotherapy, a nurse should administer an antiemetics.
Alternatives to Drugs :
Along with antiemetics, acupressure wristbands, which are available at most pharmacies, may provide some relief.
Learn more about similar type of question on adverse effect at : brainly.com/question/4297734
#SPJ4
E°cell =+1.34V
F= 96485C mol-1
3Cu(s) →3CU2+(aq) +6e-E°ck= -0.34V
2MnO4-(aq) +8H+(aq)+6e→2MnO2(s)+4H2O(l)/3CU(s) + 2MnO4-(aq)+8H+(aq)→3CU 2+((aq)+ 2MnO2(s)+4H2O (l)
E°red= +1.68V/E°cell=+1.34V
ΔG° = -nFE°cell = -6×96485×1.34 = -775.7kJ/mol
Answer:
A
Explanation:
Water is solid below 0 degrees C
Water is liquid between 0 and 100 degrees C
Water is gas above 100 degrees C