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Likurg_2 [28]
3 years ago
8

1. Diego runs a 10 kilometer race and keeps track of his speed. What was diegos speed at the kilometer mark in the race?

Mathematics
1 answer:
yulyashka [42]3 years ago
5 0

Answer: 10 km/ hr

Step-by-step explanation:

In the graph below, Diego's speed at various points during his 10 kilometer race is shown on the y axis while the distance is shown on the x axis.

Looking at the 1km mark on the x axis, Diego's speed on the y-axis is at 10km/ hr and this was the speed he started the race with. After the kilometer mark however, his speed changed and went on to increase to 11km/ hr by the second kilometer mark.

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A race car driver’s time in seconds to complete 12 laps is plotted on the graph. Why does the graph begin at x= 1?
Tcecarenko [31]
Because the y value is the time it takes to complete 1 lap.
7 0
3 years ago
an amusement park has 18 rides, 30 games, and 8 water slides. write each ratio in simplest form in two different ways
QveST [7]

Answer:

Step-by-step explanation:

<u>A three tern ratio</u>

What is a three term ratio?

A three-term ratio compares three quantities measured in the

same units.

The ratio of 18 rides, 30 games, and 8 water slides.  can be written as

18:30:8

in the simplest form it is expressed as

9:15:4

in other way it is expressed as

9 to 15 to 4

another type of ratio is the two term ratio

e,g 1:2

3 0
3 years ago
Plzz anyone solve all answers plzzzzzzzz​
algol13

You posted a lot of problems here. In the future please only post one problem at a time. Thank you.

I'll do the first two problems to get you started. Hopefully it will help you finish off the rest of the questions.

==========================================

Problem 1

{18, a, b, -3} is an arithmetic sequence or arithmetic progression (AP).

This means we have some number d added on to each term to get the next term.

first term = 18

second term = first term + d = 18+d = a

third term = second term + d = (18+d)+d = 18+2d = b

fourth term = third term + d = (18+2d)+d = 18+3d = -3

----

Let's solve that last equation for d

18+3d = -3

18+3d-18 = -3-18

3d = -21

3d/3 = -21/3

d = -7

----

The value d = -7 tells us to add -7 to each term to get the next term. In other words, we subtract 7 from each term to get the next term

first term = 18

second term = first term + d = 18+d = 18+(-7) = 18-7 = 11

third term = second term + d = 11+d = 11+(-7) = 11-7 = 4

fourth term = third term + d = 4+d = 4+(-7) = 4-7 = -3

----

We see that a = 11 and b = 4 are the second and third terms respectively.

Therefore, a+b = 11+4 = 15

-------------

<h3>Answer: 15</h3>

==========================================

Problem 2

A multiple of 4 is in the form 4*n for some integer n, ie n is a whole number.

We want to know which values of 4*n are between 10 and 250.

----

Divide both 10 and 250 by 4 to get the following

10/4 = 2.5

250/4 = 62.5

If n = 2, then 4*n = 4*2 = 8 is not between 10 and 250; however n = 3 will make 4*n = 4*3 = 12 to be between 10 and 250. We see that n = 3 is the smallest possible allowed value.

If n = 62, then 4*n = 4*62 = 248 is between 10 and 250; while n = 63 will make 4*n too big because 4*63 = 252. The largest n can get is n = 62

----

The question posed in question 2 is equivalent to asking the following: "How many values are in the set {3, 4, 5, ..., 60, 61, 62}?"

You could count all of the values in the set, but that exercise is very tedious busywork. There's a much faster way. First lets consider the set below

{a, a+1, a+2, ..., b-2, b-1, b}

where a,b are integers. Basically this set starts at 'a', counts up until we get to 'b'. The handy formula

c = b-a+1

will provide the exact count of values in the set {a, a+1, a+2, ..., b-2, b-1, b}

----

In this case, a = 3 and b = 62, making

c = b-a+1

c = 62-3+1

c = 60

There are 60 values in the set {3, 4, 5, ..., 60, 61, 62}

There are 60 multiples of four that are between 10 and 250.

-------------

<h3>Answer: 60</h3>
4 0
3 years ago
, 80 POINTS Find k so that P(k,0) is equidistant from points A(1,2) and B(2,5).
blagie [28]

Answer:

P(1.5, 3.5)

Step-by-step explanation:

We need to find the average of the x and y coordinates. We do this by adding the two values, then dividing by two:

P(x1 + x2/ 2, y1 + y2/2) = P(1 + 2/ 2, 2 + 5/ 2) = P(3/2, 7/2) = P(1.5, 3.5)

These are our coordinates!

8 0
3 years ago
Verify the identity algebraically:<br> Csc(-x)tanx =-secx
weqwewe [10]

Step-by-step explanation:

Recall that

\sin(-x) = -\sin x

Therefore,

\csc(-x) = \dfrac{1}{\sin(-x)} = -\dfrac{1}{\sin x}

so

\csc(-x)\tan x = \left(-\dfrac{1}{\sin x}\right)\left(\dfrac{\sin x}{\cos x}\right)

\:\:\:\:\:\:\:\:\:= -\dfrac{1}{\cos x} = -\sec x

5 0
2 years ago
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