If TU is 7.5 and UC is 17.5, TV = 25 because you just add the two together
(3x^2-2x+4)+(5x^2+6x-8) - Combine like terms
8x^2+4x-4
(f+g)(x)=8x^2+4x-4
Answer:
12566.4 mm²
Step-by-step explanation:
The Petri dish shown has no lid. What is the surface area of the outside of the Petri dish? Round to the nearest tenth. A cylindrical-shaped Petri dish with a radius of 50 millimeters and a height of 15 millimeters.
TSA = Total Surface Area
CSA = Curved Surface Area
TSA of open cylinder = CSA of cylinder + area of base or top
= 2πrh + πr²
= πr(2h + r)
From the above question:
r = 50mm
h = 15mm
Hence,
= π × 50 (2 × 15 + 50)
= π × 50 (30 + 50)
= π × 50(80)
= π × 4000
= 12566.370614mm²
Approximately = 12566.4 mm²
The Surface Area of the petri dish with no lid = 12566.4 mm²
For this question, we need the formula τ = F x d<span>, and just plug the numbers in.
</span>
Given the formula <span>τ = F x d</span>
Where τ = torque,
F = force applied, &
d = distance from the axis / hinge,
<span>τ = 300 c 0.8 = 240Nm</span>
Disregard the weight of the door or if there's any friction at the hinge. None of this will change the torque applied.
Answer:
multiples of 2 2,4,6,8,10,12,14,16,18,20
multiples of 3 3,6,9,12,15,,18,21,24,27,30
Step-by-step explanation:
Lcm is 6
