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jekas [21]
3 years ago
12

Two spinners divided in 3 equal sections are labeled 1 through 3 what is the probability of both spinners landing on 2

Mathematics
1 answer:
Kobotan [32]3 years ago
4 0
The answer should b 25% probability
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Find two consecutive numbers whose cubes produce a sum of 1241
MrRa [10]

8 and 9

8^3 = 512

9^3 = 729

512 + 729 = 1241

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3 years ago
5/ 10 of the students in Sam’s class are girls. Of the girls, 1 /5of them wear glasses. What fraction of all the students wear g
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1/10 because one girl out of ten students wears glasses
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Pls help or your mom will kidnap you
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A triangle has an area of 12 square millimeters. What could be the measures of the base and height of the triangle in millimeter
Harman [31]

Answer:

Step-by-step explanation:

area = ½bh = 12 mm²

bh = 24 mm²

(b,h) = (3,8) and (6,4)

7 0
3 years ago
A vector with magnitude 9 points in a direction 190 degrees counterclockwise from the positive x axis. Write in component form
Over [174]

Answer:

\vec{v}= \text{ or } \approx

Step-by-step explanation:

Component form of a vector is given by \vec{v}=, where i represents change in x-value and j represents change in y-value. The magnitude of a vector is correlated the Pythagorean Theorem. For vector \vec{v}=, the magnitude is ||v||=\sqrt{i^2+j^2.

190 degrees counterclockwise from the positive x-axis is 10 degrees below the negative x-axis. We can then draw a right triangle 10 degrees below the horizontal with one leg being i, one leg being j, and the hypotenuse of the triangle being the magnitude of the vector, which is given as 9.

In any right triangle, the sine/sin of an angle is equal to its opposite side divided by the hypotenuse, or longest side, of the triangle.

Therefore, we have:

\sin 10^{\circ}=\frac{j}{9},\\j=9\sin 10^{\circ}

To find the other leg, i, we can also use basic trigonometry for a right triangle. In right triangles only, the cosine/cos of an angle is equal to its adjacent side divided by the hypotenuse of the triangle. We get:

\cos 10^{\circ}=\frac{i}{9},\\i=9\cos 10^{\circ}

Verify that (9\sin 10^{\circ})^2+(9\cos 10^{\circ})^2=9^2\:\checkmark

Therefore, the component form of this vector is \vec{v}=\boxed{}\approx \boxed{}

6 0
3 years ago
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