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3 years ago

Two spinners divided in 3 equal sections are labeled 1 through 3 what is the probability of both spinners landing on 2

Mathematics

1 answer:

Kobotan [32]3 years ago

4 0

The answer should b 25% probability

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926/71 Explain how u got the answer

Gala2k [10]

Answer:

Step-by-step explanation:

926/71 = 13 Remainder 3

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3 years ago

FI have no points left please answer, FLIP THE IMAGE OVER PLS

Nezavi [6.7K]

Answer:

Step-by-step explanation:

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3 years ago

What is the surface area of a triangular prism?

Llana [10]

Answer:

The general formula for the total surface area of a right prism is T. S. A. =ph+2B where p represents the perimeter of the base, h the height of the prism and B the area of the base.

Step-by-step explanation:

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3 years ago

If ON= 5x - 7, LM = 4x+ 4, NM = x -7, and OL =3y-4, find the values of c and y for which LMNO MUST BE a parallelogram.

Sholpan [36]

Answer:

x=11, y=8/3

Step-by-step explanation:

Consider quadrilateral LMNO. If this quadrilateral MUST BE a parallelogram, then

LM=NO

and

LO=MN

Thus,

$\left\{\begin{array}{l}4x+4=5x-7\\ \\x-7=3y-4\end{array}\right.$

Solve this system of two equations. From the first equation:

$4x-5x=-7-4\\ \\-x=-11\\ \\x=11$

Substitute it into the second equation:

$11-7=3y-4\\ \\3y-4=4\\ \\3y=4+4\\ \\3y=8\\ \\y=\dfrac{8}{3}$

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3 years ago

Area of the shaded segment=

garik1379 [7]

The area of the entire sector is $(\pi)(6^{2}) \left(\frac{60}{360} \right)=6\pi$

The area of the triangle OAB is $\frac{\sqrt{3}}{4}(6^{2})=9\sqrt{3}$ .

So, the area of the segment is $\boxed{6\pi-9\sqrt{3}}$

5 0

2 years ago