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Mathematics

1 answer:

kramer3 years ago

4 0

Answer:

What question are you referring to? a question references question 5 and 6 which aren't displayed.

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Identify the equation of a line in slope-intercept form that is perpendicular to y = -1/3 x + 2 and passes through (2, 1)

Airida [17]

Answer:

Step-by-step explanation:

The slope of a line perpendicular to another line is the opposite reciprocal of the slope of the other line, meaning if the slope of the other line is $-\frac{1}{3}$ , then the slope of the line perpendicular is $3$ .

Knowing this, we can start to construct the equation for the line:

$y = mx + b$

$y = 3x + b$

To solve for $b$ , we plug in the coordinates of the point that we know the line runs through, $(2, 1)$ :

$y = 3x + b$

$1 = 3(2) + b$

$1 = 6 + b$

$b = -5$

Therefore, the slope of the line that is perpendicular ot the line provided in the equation is the following:

$y = 3x - 5$

5 0

3 years ago

Write an answer in the form of rooted ax+b=x+c

MA_775_DIABLO [31]

Lets solve for a
ax+b=x+c
step 1:add -b to both sides
ax+b-b=c+x+-b
step 2:divide both sides
ax=-b+c+x
ax/x=-b+c+x/x
a=-b+c+x/x
answer:
a=-b+c+x/x

5 0

3 years ago

What is the following product? Sqr5x^8y^2 sqr10x^3 sqr12y

PSYCHO15rus [73]

Step-by-step explanation:

$\sqrt{5 {x}^{8} {y}^{2} } \times \sqrt{10 {x}^{3} } \times \sqrt{12y} \\ \\ = {x}^{4} y \sqrt{5} \times x \sqrt{10x} \times 2 \sqrt{3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 10x \times 3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 5 \times 2x \times 3y} \\ \\ = 2 {x}^{5} y \times 5\sqrt{ 2x \times 3y} \\ \\ = 10 {x}^{5} y \sqrt{6xy} \\$