ANSWER

EXPLANATION
The dimensions of a matrix is of the form:

The dimensions of the first matrix is

The dimensions of the second matrix is

Since the inner products are the same,the outer products give the dimensions of the product of the two matrices.

Therefore the dimensions of the product is a 2×2 matrix.
A, because negative is not rational
The answer is on google no dumb stuff dummy
Answer:
dfghfegfefehfgfe
Step-by-step explanation:
tyfvrfvewfgwvehgew e
Answer:
sorry if im wrong i think wrong numbers. plz check
Step-by-step explanation:
The center of dilation of the question is (-4,-3) .
let say that
x0=-4
y0=-3
Label the image A'B'C'
The new coordinate would be
A(-4,-1)
x=4
y=-1
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-1 +3)
y'=-3 +4= 1
______________________________
B(-4,-3)
x=-4
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-4 +4)
x'=-4
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
______________________________
C(-1,-3)
x=-1
y=-3
x'=x0+ 2(x - x0)
x'= -4+ 2(-1 +4)
x'=-4 +6= 2
y'=y0+ 2(y - y0)
y'= -3+ 2(-3 +3)
y'=-3
A'(-4,1)
B'(-4,-3)
C'(2,-3)