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3 years ago

What’s the median of 70,77,80,81,82,87,88

Mathematics

2 answers:

son4ous [18]3 years ago

4 0

Answer:

The median is 81.

Step-by-step explanation:

You can find the median in the middle if it all of them add up to odd.(like your’s say 70, 77, 80,... so that You will count them all. In total you have seven numbers and it’s odd).

if it is an even numbers, you mulitply the middle two numbers and divide them by two. That is the median for even numbers.

Galina-37 [17]3 years ago

3 0

Answer:

Hello There!!

Step-by-step explanation:

You order them but in this case they are already ordered and the middle number is 81 so that is the median(also knows as the middle).

hope this helps,have a great day!!

~Pinky~

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3 years ago

A cookie factory monitored the number of broken cookies per pack yesterday.

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Answer:

Confidence Interval - 2.290 < S < 2.965

Step-by-step explanation:

Complete question

A chocolate chip cookie manufacturing company recorded the number of chocolate chips in a sample of 50 cookies. The mean is 23.33 and the standard deviation is 2.6. Construct a 80% confidence interval estimate of the standard deviation of the numbers of chocolate chips in all such cookies.

Solution

Given

n=50

x=23.33

s=2.6

Alpha = 1-0.80 = 0.20

X^2(a/2,n-1) = X^2(0.10, 49) = 63.17

sqrt(63.17) = 7.948

X^2(1 - a/2,n-1) = X^2(0.90, 49) = 37.69

sqrt(37.69) = 6.139

s*sqrt(n-1) = 18.2

$s\sqrt{\frac{n-1}{X^2 _{(n-1), \frac{\alpha }{2} } }$ $\leq \sigma \leq s\sqrt{\frac{n-1}{X^2 _{(n-1), 1-\frac{\alpha }{2} } }$

confidence interval:

(18.2/7.948) < S < (18.2/6.139)

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3 years ago

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3 years ago

Read 2 more answers

What is the solution to <br> 4/a+5/3a<3

scoray [572]

$\dfrac{4}{a}+\dfrac{5}{3a} < 3\ \ \ |-3\ \ \ assume\ a\neq0\\\\\dfrac{3\cdot4}{3a}+\dfrac{5}{3a}-\dfrac{3a\cdot3}{3a} < 0\\\\\dfrac{12+5-9a}{3a} < 0\\\\\dfrac{-9a+17}{3a} < 0\iff 3a(-9a+17) < 0\\\\3a=0\to a=0\\\\-9a+17=0\to a=\dfrac{17}{9}$
Look at the picture.
$Answer:\ a\in\left(0;\ \dfrac{17}{9}\right)$

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3 years ago