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Nastasia [14]
3 years ago
7

If a die is rolled one time, find probability of getting a number greater than 3 and an odd number.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
4 0

Answer:

\dfrac{1}{6}.

Step-by-step explanation:

It is given that a die is rolled one time. So,

Sample space : S=\{1,2,3,4,5,6\}

Number is greater than 3 : A=\{4,5,6\}

Number is odd : A=\{1,3,5\}

Number greater than 3 and an odd number : A\cap B=\{5\}

It is conclude that,

n(S)=6, n(A)=3,n(B)=3,n(A\cap B)=1

The probability of getting a number greater than 3 and an odd number is

P=\dfrac{n(A\cap B)}{n(S)}

P=\dfrac{1}{6}

Therefore, the required probability is \dfrac{1}{6}.

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