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3 years ago

If cheese is 4.40 per kilogram, what should I pay for 200 grams

Mathematics

2 answers:

N76 [4]3 years ago

6 0

200 grams is is 0.2 kilograms, so you would pay $0.88 because 4.40x0.2=0.88

Lapatulllka [165]3 years ago

5 0

Answer: You should pay $0.88 or 88 cents for 200 grams.

Step-by-step explanation:

We are given that : The price of cheese = $ 4.40 per kilogram

i.e. One kilogram of cheese costs = $4.40

We know that 1 kilogram = 1000 grams

⇒ The price of 1000 grams of cheese = $4.40

⇒ The price of 1 gram of cheese = $\dfrac{\$4.40}{1000}$ [By unitary method]

⇒ The price of 200 grams of cheese = $200\times\dfrac{\$4.40}{1000}$ [By unitary method]

$=\$0.88$

Hence, you should pay $0.88 or 88 cents for 200 grams.

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Juliette [100K]

Answer:

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Step-by-step explanation:

step 1

Find the volume of the conical cup

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$h=4\ in$

assume

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substitute

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3 years ago

-4x + 8 equals 2 (x + 6)

aliina [53]

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3 0

3 years ago

An airplane has 100 seats for passengers. Assume that the probability that a person holding a ticket appears for the flight is 0

zmey [24]

Answer:

96.33% probability that everyone who appears for the flight will get a seat

Step-by-step explanation:

I am going to use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

$n = 105, p = 0.9$

$\mu = E(X) = np = 105*0.9 = 94.5$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.9*0.1} = 3.07$

What is the probability that everyone who appears for the flight will get a seat

100 or less people appearing to the flight, which is the pvalue of Z when X = 100. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{100 - 94.5}{3.07}$

$Z = 1.79$

$Z = 1.79$ has a pvalue of 0.9633

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3 years ago

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3 years ago

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pickupchik [31]

Answer:

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Step-by-step explanation:

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