Answer:
The function that represents the mass of the sample after t days is 
.
The percentage rate of change per hour is of -2.46%.
Step-by-step explanation:
Exponential amount of decay:
The exponential amount of decay for an amount of a substance after t days is given by:
In which A(0) is the initial amount, and r is the decay rate, as a decimal.
Element X is a radioactive isotope such that its mass decreases by 59% every day. The experiments starts out with 390 grams of Element X.
This means, respectively, that 
So
The function that represents the mass of the sample after t days is .
Hourly rate of change:
Decreases by 59% every day, which means that for 24 hours, the rate of change is of -59%. So
-59%/24 = -2.46%
The percentage rate of change per hour is of -2.46%.
Answer:
The P-value is 0.0234.
Step-by-step explanation:
We are given that a statistics practitioner calculated the mean and the standard deviation from a sample of 400. They are x = 98 and s = 20.
Let = population mean.
So, Null Hypothesis, : = 100 {means that the population mean is equal to 100}
Alternate Hypothesis, : > 100 {means that the population mean is more than 100}
The test statistics that will be used here is One-sample t-test statistics because we're yet to know about the population standard deviation;
T.S. = ~
where, = sample mean = 98
s = sample standard deviation = 20
n = sample size = 400
So, the test statistics = ~
= -2
The value of t-test statistics is -2.
Now, the P-value of the test statistics is given by;
P( < -2) = 0.0234 {using the t-table}
Answer:
nice
Step-by-step explanation:
I drew it out. Hope this helps.
23/6 as a mixed fraction is 3(5/6)
