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natulia [17]
3 years ago
10

Erin has a $20 bill with which to buy coffee . If she buys 2 pounds of ground coffee at $4 per pound and spends the rest on gour

met coffee at $8 per pound how many pounds of gourmet coffe can she buy?
Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
6 0
Since she already spent $8 for 2 pounds of the ground coffee, she now has $12 left so then she can only buy only 1 pound of gourmet coffee since she will only have $4 left after buying the first pound.
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podryga [215]

Answer:

the first answer

Step-by-step explanation:

8 0
3 years ago
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Pooja's plant began sprouting 2 days before Pooja bought it, and she had it for 98 days until it died. At its tallest, the plant
r-ruslan [8.4K]

Solution:

Total number of Days that Pooja's plant survived= 2 + 98 = 100 Days=(t)

Longest Height obtained by plant = 30 cm= h

As the two , i.e number of Days lived by plant and it's longest height obtained are directly proportional.

We will solve it by unitary method.

100 Days = 30 cm

1 cm =  Days

If height of the plant is h cm ,and  amount of time taken is t days, then

h(t) cm = ,for t=0,1,2,3,4,5,6....we get different values of h.

7 0
3 years ago
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A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co
Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let \mu = <u><em>mean weight of coffee in its containers.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq 32 ounces     {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, H_A : \mu < 32 ounces      {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here <u>One-sample t-test statistics</u> as we don't know about population standard deviation;

                             T.S. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean weight = 31.8 ounces

             s = sample standard deviation = 0.48 ounces

             n = sample of containers = 15

So, <u><em>the test statistics</em></u>  =  \frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }  ~ t_1_4  

                                      =  -1.614

The value of t test statistics is -1.614.

<u>Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.</u>

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which <u><em>we fail to reject our null hypothesis</em></u>.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

8 0
3 years ago
A line of best fit predicts that when x equals 28, y will equal 27.255, but y actually equals 26. What is the residual in this c
zlopas [31]

Answer:

C) -1.255

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

Residual value =  26 - 27.255

Residual values = -1.255

The answer is -1.255 for residual value.

5 0
2 years ago
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