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LenKa [72]
3 years ago
13

There are two numbers which sum to 23. If one number is seven less than four times the other, find the numbers.

Mathematics
1 answer:
mart [117]3 years ago
8 0

Answer:

Numbers are 6 and 17.

Step-by-step explanation:

Let the two numbers are 'a' and 'b'.

"Sum of these numbers = 23"

a + b = 23 --------(1)

"One number is 7 less than 4 times the other"

a = 4b - 7 ---------(2)

Substitute the value of 'a' in equation (1) from equation (2)

(4b - 7) + b = 23

5b - 7 = 23

5b = 23 + 7

5b = 30

b = 6

From equation (2),

a = 4b - 7

a = 4×6 - 7

a = 24 - 7

a = 17

Therefore, the numbers are 6 and 17.

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Hope this helps

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Niki makes the same payment every two months to pay off his $61,600 loan. The loan has an interest rate of 9.84%, compounded eve
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8 0
3 years ago
Read 2 more answers
Please EXPLAIN how to get this answer so I can do it with other problems. A straight answer would be great, but I have to do abo
OLEGan [10]

Answer:

PQ = 3.58, and RQ = 10.4

Step-by-step explanation:

We are given the hypotenuse of the triangle, and an angle. Use sin and cos to solve.  

Hypotenuse = 11,

Opposite side is PQ

Adjacent side is RQ

x = 19

Sin x  = (opposite side)/(hypotenuse)

Cos x = (adjacent side)/(hypotenuse)

For PQ, this is the side opposite to the angle, so use sin,

Sin 19 = x/11

   11(Sin 19) = x

        3.58 = x        (rounded to the nearest hundredth)            

For RQ, this is the side adjacent to the angle, so use cos,

Cos 19 = x/11

   11(Cos 19) = x

        10.4 = x        (rounded to the nearest hundredth)        

6 0
3 years ago
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