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3 years ago

ILL GIVE BRAINLIEST!!!! Find the shaded region and its area

Mathematics

2 answers:

beks73 [17]3 years ago

8 0

Answer:

shaded area is 50.24

Step-by-step explanation:

how it got solved? Area’s formula is pi * radius squared. Since we have the 3 as the radius, we square that which gives us nine. 3.14 multiplied by nine is 28.26. Let’s solve the other circle. pi times 5 squared which is 25. 3.14 times 25 is 78.5

78.5 minus 28.26 is 50.24 so therefore, that’s the answer (don’t forget to add the small 2 at the top of ur answer)

(sorry if it’s wrong)

Stolb23 [73]3 years ago

6 0

Answer:area is 15cm please give me brainlest also a small 2 at the top of 15cm

Step-by-step explanation:

You might be interested in

Plz help me find these functions!

Iteru [2.4K]

Answer:

$\sin \alpha = \frac{5}{13}$ , $\cos \alpha = \frac{12}{13}$ , $\tan \alpha = \frac{5}{12}$ , $\cot \alpha = \frac{12}{5}$ , $\sec \alpha = \frac{13}{12}$ , $\csc \alpha = \frac{13}{5}$

Step-by-step explanation:

The angle $\alpha$ is the angle opposite to the side of length 5 and adjacent to the side of length 12. From Trigonometry we remember the following relationships:

$\sin \alpha = \frac{5}{\sqrt{5^{2}+12^{2}}}$

$\sin \alpha = \frac{5}{13}$

$\cos \alpha = \frac{12}{\sqrt{5^{2}+12^{2}}}$

$\cos \alpha = \frac{12}{13}$

$\tan \alpha = \frac{5}{12}$

$\cot \alpha = \frac{12}{5}$

$\sec \alpha = \frac{\sqrt{5^{2}+12^{2}}}{12}$

$\sec \alpha = \frac{13}{12}$

$\csc \alpha = \frac{\sqrt{5^{2}+12^{2}}}{5}$

$\csc \alpha = \frac{13}{5}$

4 0

3 years ago

Given these two data sets, IQ-GPA and IQ-SAT, how would you predict Justin’s SAT score based on his GPA? Explain.

daser333 [38]

Answer:

First, use the equation of the trend line to find the IQ that is expected by the GPA. Next, use the other equation of the trend line to find the SAT that is predicted by the IQ.

Step-by-step explanation:

have a great day!

8 0

3 years ago

Read 2 more answers

Can you please help me again.

Jobisdone [24]

Answer: h = 17

Step-by-step explanation: As a general rule, if an equation has any fractions in it, try to get rid of those fractions as soon as possible.

The quickest way to get rid of a fraction is to multiply both

sides of the equation by the denominator of the fraction.

So in this problem, we can get rid of the fraction in our