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andrey2020 [161]
3 years ago
10

I'll give Brainliest to whoever answers right and first.

Mathematics
1 answer:
polet [3.4K]3 years ago
3 0
The correct answer is C
(X-5)²+(Y-7)²=50
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Answer: C all real numbers

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30 random samples of high school students were asked if they played a sport for their high school. Each sample was 20 students.
Ludmilka [50]

Answer:

<em>a. This option is correct</em>

<em>b. This will be true only if we take the </em><em>mode</em><em> as the best representative value </em>

c. <em>This is a correct choice</em>

<em>d. This is not a correct choice</em>

Step-by-step explanation:

<u>Statistics</u>

We are given a dot plot representing 30 random sample proportions of high school students about their sports activities. Based on the data extracted from the plot, we can make some basic conclusions and, less accurately, some predictions.

From the data plot we can see that the following proportions were obtained, along with their absolute frequencies:

0.05 -> 3

0.10 -> 8

0.15 -> 7

0.20 -> 5

0.25 -> 4

0.30 -> 2

Let's select which of the following options are correct

a. A sample proportion of 0.20 means that 4 of 20 high school students responded that they play a sport.

The ratio between the sport playing students to the total of high school students is

\displaystyle \frac{4}{20}=\frac{1}{5}=0.20

Thus, this statement is correct.

b. The best prediction for the proportion of all high school students that play a sport is 0.10.

This will be true only if we take the mode as the best representative value for the whole dataset. Personally, I don't like to trust the mode as a good central tendency result, I'd prefer the mean instead.

c. The mean of the 30 sample proportions calculated to the nearest hundredth is 0.16

Computing the mean of the sample proportions

\displaystyle \bar x=\frac{\sum x_i.f_i}{\sum f_i}

\displaystyle \bar x=\frac{0.00\cdot 1+0.05\cdot 3+0.10\cdot 8+0.15\cdot 7+0.20\cdot 5+0.25\cdot 4+0.30\cdot 2}{1+3+8+7+5+4+2}

\bar x\approx 0.16

<em>This is a correct choice</em>

d. The shape of the sample distribution is fairly symmetrical

We can see the distribution if left-skewed because its peak value is not at the mean value. The mode and the mean are fairly different, thus this choice is not correct

5 0
3 years ago
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A . 900-1000

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