<span>The term that you want is 5C2*p^2*q^3
representing 2 successes and 3 failures. This term's value is</span>
<span>(5C2)(0.5^5)
= 10*0.03125 = 0.3125 = P(2 successes in 5 trials) =31.3% </span>
Answer: x = 40.81 or 41
Step-by-step explanation:
A = B = 21
C = 35
Hypotenuse = x
Calculating Hypotenuse:
21^2 + 35^2 = x^2
=> 441 + 1225 = x^2
=> x^2 = 1666
=> x = 40.81 or 41
Answer:
No
Step-by-step explanation:
Given that:
Amount earned when a student does comminty service = $5
Number of students in club = 12
Amount earned E, is a function of number of members (n) who does community service.
Hence,
E = n * amount earned per member
Is 24 a possible output?
To test, then E = 24
24 = n * 5
24 = 5n
24/5 = 5n/5
4.8 = 5
Hence, 24 is not a possible output, be use number of membwra cannot be a decimal
The average of those five amounts is 183,636.7
AVeraging is adding all of the numbers together with the dividing by a number of numbers you have.
I think the Caldwell family (tbh I don’t know ♀️)
