Answer:
the answer will be 30 mikes per hour
Step-by-step explanation:
(ax-by)²+(bx+ay)²
a²x²-2axby+b²y²+b²x²+2axby+a²x²
a²x²+b²x²+b²y²+a²x²
(a²+b²)x²+(a²+b²)y²
(a²+b²)(x²+y²)
Answer:
18≤ 2.50x
because there is only so much money she is allowed to spend has to be less than or equal to 18
Hope it helps u..............
For this problem, let's assign variables for the unknown parameters. Let x be the value for student tickets, while y be the value for chaperone tickets. The two equations formulated would be:
59x + 6y = 508 --> eqn 1
x = 2+y --> eqn 2
Rearranging eqn 2,
y = x - 2
Substituting this to eqn 1 and solving for x,
59x + 6(x - 2) = 508
59x + 6x - 12 = 508
x = 8
Thus, each student ticket costs $8.
