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Bingel [31]
3 years ago
14

According to the line plot, how much more is the total weight of the 1/2 of a pound dog toys than the weight of the 5/8 of a pou

nd dog toys?
Mathematics
1 answer:
USPshnik [31]3 years ago
6 0
You didn’t attach the line plot but I’ll do my best.

1 pound = 16 ounces

It says of a pound dog toys, meaning that we will have to do multiplication:

1/2 * 1 pound

= 1/2 * 16 ounces

= 8 ounces

5/8 * 16 ounces

= 10

Next, find the difference:

10 - 8 = 2

The total weight of 5/8 of a pound of dog toys is 2 ounces greater than 1/2 of a pound of dog toys.


Also, the last bit of the question is worded incorrectly. 5/8 > 1/2 right off the bat. I’m not sure who designed the question but I think you should let them know since it would likely confuse individuals who encounter this question. Hope this helps!
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First we need to figure out how many total ounces the fish weighs.

Since there is 16oz in a pound, we just need to multiply 31 by 16 which equals 496oz. We also need to add 12 because the fish weighed 31 pounds and 12oz.

496 + 12 = 508

Okay, so now that we have the total amount of ounces that the fish weighs, we can divide it by the average serving size (6oz)

508 ÷ 6 = 84.66666....

84.66666 can be rounded to 85

Therefore, the fish has about 85 servings

Hope this helps

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3 years ago
What adds to equal 0 but multiplies to equal -4000?
alukav5142 [94]
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Calculate the length of AB using Sine rule
vovikov84 [41]

Answer:

Approximately 22.2\; \rm m.

Step-by-step explanation:

By sine rule, the length of each side of a triangle is proportional to the sine value of the angle opposite to that side. For example, in this triangle \triangle ABC, angle \angle A is opposite to side BC, while \angle C is opposite to side AB. By sine rule, \displaystyle \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C}.

It is already given that BC = 22.4\; \rm m and \angle A = 58^\circ. The catch is that the value of \angle C needs to be calculated from \angle A and \angle B.

The sum of the three internal angles of a triangle is 180^\circ. In \triangle ABC, that means \angle A + \angle B + \angle C = 180^\circ. Hence,

\begin{aligned}\angle C &= 180^\circ - \angle A - \angle B \\ &= 180^\circ - 58^\circ - 65^\circ \\ &= 57^\circ\end{aligned}.

Apply the sine rule:

\begin{aligned} & \frac{BC}{\sin{\angle A}} = \frac{AB}{\sin \angle C} \\ \implies & AB = \frac{BC}{\sin{\angle A}} \cdot \sin \angle C  \end{aligned}.

\begin{aligned}AB &= \frac{BC}{\sin{\angle A}} \cdot \sin \angle C \\ &= \frac{22.4\; \rm m}{\sin 58^\circ} \times \sin 57^\circ \\ &\approx 22.2\; \rm m\end{aligned}.

5 0
3 years ago
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LenKa [72]

Answer:

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Step-by-step explanation:

(a+b)²=a²+b²+2ab

(12)²=a²+b²+2×9

144=a²+b²+18

a²+b²=144-18=126

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3 years ago
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