A number is a perfect square (or a square number) if its square root is an integer; that is to say, it is the product of an integer with itself. Here, the square root of 20 is about 4.472. Thus, the square root of 20 is not an integer, and therefore 20 is not a square number.
Answer:
Step-by-step explanation:
It’s a repeating pattern.
i² = -1
i³ =(i²)i = (-1)i = -i
i⁴ = i³i = -i² = 1
i⁵ = (i⁴)i = (1)i = i
i⁶ = i⁵i = i² = -1
...
i¹⁷ = i
True, because 4.2 is a lot lower than 55.3, 73.4, 89.3, and 132.2.
Answer: q = -13
Step-by-step explanation:
(q+5)/4 = -2 first you multiply 4 to remove denominators
(q+5) = -8 then subtract 5
q = -13
Answer: C
Step-by-step explanation:
For this problem, we need to know the standard form of a sine function and the meaning of each part.
Standard form: ![y=asin[b(x-h)]+k](https://tex.z-dn.net/?f=y%3Dasin%5Bb%28x-h%29%5D%2Bk)
a=amplitude
b=period
h=phase shift
k=vertical replacement/shifting
Now that we know the standard form and the components, we know that we can forget about k and plug in 0 for h. This would leave us with ![y=asin[b(x)]](https://tex.z-dn.net/?f=y%3Dasin%5Bb%28x%29%5D)
. We know that the amplitude is 2, therefore, a=2. To find the period, you divide 2π by the given period. 
, therefore, b=1/2.
[plug in a=2]
![y=2sin[b(x)]](https://tex.z-dn.net/?f=y%3D2sin%5Bb%28x%29%5D)
[plug in b=1/2]
Therefore, C is the correct answer.
