Solve the equation on the interval 0 less than or equals theta less than 2 pi .0≤θ<2π. secant StartFraction 5 theta Over 4 En
1 answer:
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First picture:
You got the first two right (good job!), so I'll just tackle the third one. If you have to compute , it means that you have to substitute
in place of
. Differently from the first two points, this will generate a new function, rather than a specific value:
Second picture:
Given the point highlighted in the picture, you can deduce that the base is
units long (since it spans from
to
) and the height is
units long (because it spans from
to
). So, the area of the rectangle is the multiplication between base and height:
But we know that , so we have
The domain of this function is given by the domain of the square root: we want its argument to be non, negative, so we have
But since the problem is symmetric, the answer is
You can only see the answer because, if you choose
or
, the rectangle degenerates to a segment, and your exercise doesn't like this scenario, apparently
