Re read the question again just in case, try and put £25.50
But I got 25.5 too
Answer:
thats easy
Step-by-step explanation:
but thanks 4 the points
Answer:
Step-by-step explanation:
Step-by-step explanation:
- 0.06
- 60%
- 2/3
- 3/4
hope it's right :)
Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
