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Tresset [83]
2 years ago
15

Please help me i really need help thank you

Mathematics
1 answer:
bagirrra123 [75]2 years ago
4 0
Noooooo dontttttt presssss link
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How do I work this problem out? <br> S= 2(lw+ lh+ wh)
ANTONII [103]
First, and most important, you must know what the question is. You haven't told us what the question is, and a gray cloud hangs like a dark mist over the problem, giving the unmistakable impression that you're not too sure of it yourself.
7 0
3 years ago
NEED HELP FAST PLEASE<br> Evaluate the limit.<br><br> a.4<br> c.1<br> b.2<br> d.limit does not exist
BlackZzzverrR [31]
We have the following limit:
 (8n2 + 5n + 2) / (3 + 2n)
 Evaluating for n = inf we have:
 (8 (inf) 2 + 5 (inf) + 2) / (3 + 2 (inf))
 (inf) / (inf)
 We observe that we have an indetermination, which we must resolve.
 Applying L'hopital we have:
 (8n2 + 5n + 2) '/ (3 + 2n)'
 (16n + 5) / (2)
 Evaluating again for n = inf:
 (16 (inf) + 5) / (2) = inf
 Therefore, the limit tends to infinity.
 Answer:
 
d.limit does not exist
7 0
3 years ago
What is the difference of 15 and 23=
Evgesh-ka [11]
Just simply subtract 23 by 15 to get the difference of 8

4 0
3 years ago
Read 2 more answers
Please please help I’ll give the brain thing if you help but you need to have a correct answer + explain thanks :)))
Alecsey [184]

Answer:

i really dont know im in 7th grade im so sorry

Step-by-step explanation:

7 0
2 years ago
A TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 500
nekit [7.7K]

Answer:

0.903264

Step-by-step explanation:

Given that a TV set contains five circuit boards of type A, five of type B, and four of type C. The probability of failing in its first 5000 hours of use is 0.03 for a type A circuit board, 0.04 for a type B circuit board, and 0.03 for a type C circuit board.

Let A' = the event that A fails, B' =  B fails and C'= C fails.

Probability that no circuit board fails = Prob (A'B'C')

= P(A')P(B')P(C')  (since A,B, C are independent, their complements are independent

= (1-0.03)(1-0.04)(1-0.03)

= 0.903264

8 0
3 years ago
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