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3 years ago

Solve for c. -3b+ac=c-4. Please show all work.

2 answers:

8 0

-3b + ac = c - 4
+ 4 - ac = - ac + 4

-3b + 4 = -ac + c

-ac + c = c(-a + 1)

-3b + 4/-a + 1 = c

i hope i explained it well

Luden [163]3 years ago

6 0

-3b+ac=4
Move c to the left and - 3b to the right
ac-c=-4+3b
Now factor by c at the left
c(a-1)=-4+3b
Divide the right by a-1
C=(-4+3b)/(a-1)

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Liliana wants to determine the height of an enlarged photo that she plans to frame. The original photo was 11 inches wide by 14

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For this case, the first thing we must do is find the scale factor.

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3 years ago

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4x + 1 = 5, find x assuming x is a whole number

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Answer:

x=1

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4x+1=5

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3 years ago

What can you conclude about the setting, based on this passage? Buck is in the north, where sled dogs are in demand. Buck is exp

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Answer:

We can conclude that the setting is stationed somewhere in the north where it's very cold, so cold that they can use sled dogs. We can also assume it's winter time because it normally snows during the winter.

So the setting is in the north where it is cold, during the winter time.

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2 years ago

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Find dy/dx by implicit differentiation for x – y = xy.

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Answer:

$\frac{dy}{dx}$ = $\frac{1-y}{1+x}$

Step-by-step explanation:

Differentiate xy using the product rule, then

Given

x - y = xy

1 - $\frac{dy}{dx}$ = x. $\frac{dy}{dx}$ + y. 1 = x $\frac{dy}{dx}$ + y ( subtract 1 from both sides )

- $\frac{dy}{dx}$ = x $\frac{dy}{dx}$ + y - 1 ( subtract x $\frac{dy}{dx}$ from both sides )

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3 years ago

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A church is bringing a group of its members to a "clean comedians" show. If they bring 15 people, it will cost $10 each. For eac

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Answer:

a) $169.2

b) $202.8

c) the church can bring either 31 or 34 members

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For each person the church brings that exceeds 15, the ticket price goes down by $0.20

18 members exceed 15 by 3.

This means that for 3 persons the church brings that exceeds 15, we have 3*0.20 = $0.60

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b) The model for bringing a number of people at a particular cost = C(x)

x is the number of people that exceeds 15

C(x) = (15+x)(10-0.2x)

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= 150 + 7x - 0.2x^2

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= $202.8

c) if the church can only afford $210.8, to solve x, we have

150 + 7x - 0.2x^2 = 210.8

-0.2x^2 + 7x + 150 = 210.8

-0.2x^2 + 7x + 150 - 210.8 = 0

-0.2x^2 + 7x -60.8 = 0

(-b +/-√b^2 - 4ac) / 2a

a = -0.2 , b = 7 c = -60.8

(-7 +/-√7^2 - 4(-0.2)(-60.8)) / 2(-0.2) = 0

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(-7 +/-√0.36) / -0.4 = 0

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(-7+0.6)/-0.4 or (-7 - 0.6)/-0.4

(-6.4)/-0.4 or (-7.6)/- 0.4

16 or 19

So we have (15+16) = 31 members

(15+19) = 34 members

The church can bring either 31 members or 34 members

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3 years ago