I think it would be something like this: x-80 = (x*2)+12
Answer:
1.320 ,
2.322
Step-by-step explanation:
1. Given that,
a+1/a=18
now,
(a- 1/a)² =( a+1/a)² - 4a. 1/a [(a- b)² =( a+b)² - 4a. b ]
=18² - 4 . 1 [as, a . 1/a =1 ]
=324 - 4
=320
2.Given that,
a - 1/a=4
now,
a⁴+(1/a)⁴
=(a²)² + (1/a²)² [a⁴=(a²)² & (1/a)⁴=(1/a²)²]
=(a²+1/a²) ²- 2 a². (1/a²) [a²+b²=(a+b)²-2ab]
=[(a - 1/a)² +2.a. 1/a]² - 2 [a²+b²=(a-b)²+2ab]
=[4²+2]² -2
=[16+2]²-2
=18²-2
=324-2
=322
Answer:
cot(θ)=5/12
Step-by-step explanation:
(I'm going to replace theta with x to save time.)
Recall that sine is equal to opposite over hypotenuse. Thus:
sin(x)=12/13, this means that the opposite side is 12 while the hypotenuse is 13 (well, it doesn't have to be, but their ratios are).
Find the adjacent side using the Pythagorean Theorem.
13^2 = 12^2 + adj^2
adj^2 = 25
adj = 5.
Recall that tan(x) is opposite over adjacent. This means that cot(x) is adjacent is opposite.
Therefore: cot(x) = 5/12.
Answer:
number one answer: 5
Step-by-step explanation:
equal sides just divide by 4 for the smaller one
Answer:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Suppose a sample of 292 tenth graders is drawn. Of the students sampled, 240 read above the eighth grade level.
So 292 - 240 = 52 read below or at eight grade level, and that 
80% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 80% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.149, 0.207).
