Act 4. Scene 5
1 answer:
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15 students are in each van and 51 students are in each bus
<em><u>Solution:</u></em>
Let "x" be the number of students in each van
Let "y" be the number of students in each bus
<em><u>The senior class at High School A rented and filled 11 vans and 9 buses with 624 students</u></em>
Therefore, a equation is framed as:
11 vans x number of students in each van + 9 buses x number of students in each bus = 624
11x + 9y = 624 ------- eqn 1
<em><u>High School B rented and filled 5 vans and 1 bus with 126 students</u></em>
Therefore, a equation is framed as:
5 vans x number of students in each van + 1 buses x number of students in each bus = 126
5x + y = 126 ---------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
y = 126 - 5x ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
11x + 9(126 - 5x) = 624
11x + 1134 - 45x = 624
-34x = 624 - 1134
-34x = -510
34x = 510
<h3>x = 15</h3><em><u>Substitute x = 15 in eqn 3</u></em>
y = 126 - 5(15)
y = 126 - 75
<h3>y = 51</h3>Thus 15 students are in each van and 51 students are in each bus